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Anarel [89]
3 years ago
5

HELP!!! me plz I don’t get it!!!!

Mathematics
1 answer:
fomenos3 years ago
7 0
Answer: 3/2, 1 1/2 or 1.5
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4 years ago
Solve each equation using the quadratic formula. Find the exact solution, then approximate the solution to the nearest hundredth
Anika [276]

Answer:

x_1=\frac{5+\sqrt{33}}{4}≈2.69

x_2=\frac{5-\sqrt{33}}{4}≈-0.19



Step-by-step explanation:

 To solve this problem you  must apply the proccedure shown below:

1. You have that the quadratic formula is:

x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}

2. To solve the quadratic equation you must substitute the values. So, you have that:

Rewrite the equation:

2x^{2}-5x-1=0

a=2\\b=-5\\c=-1

Then you have:

 x=\frac{-(-5)+/-\sqrt{(-5)^{2}-4(2)(-1)}}{2(2)}

3. Therefore, you obtain the following result:

x_1=\frac{5+\sqrt{33}}{4}≈2.69

x_2=\frac{5-\sqrt{33}}{4}≈-0.19


4 0
3 years ago
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How do you add with a negative number?
Cloud [144]
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2 years ago
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Is the square root of two rational numbers
marysya [2.9K]


1 I think...............
7 0
3 years ago
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laiz [17]

Answer:

B)

Step-by-step explanation:

For the function y=-5x, all coordinates this line passes through should make this inequality true.

\begin{case}y=5(-7)=35\\y=-2(-5)=10\\y=2(-5)=-10\end{case}

This corresponds with table B.

7 0
3 years ago
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