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3 years ago

Please help!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

larisa [96]3 years ago

7 0

Your answer is D) 2 2/25

serious [3.7K]3 years ago

6 0

Answer:

Your answer with be D :))

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Don went to his favorite restaurant and ordered a meal. His bill came out to $15.77. He wants to pay a 15% tip. How much did he

melamori03 [73]

You want to leave a 15% tip on a meal that cost $15.77.
First, convert the 15% to an actual number that can be used in a calculation. For percents,this is always done by simply dividing the percent (in this case 15%) by 100%.So, the conversational term "15%" becomes 15% / 100% = 0.15 in terms of a real mathematical number.
Second, you need to find out what 15% of your $15.77 meal cost is.This is always done by multiplying 0.15 by $15.77, or

0.15 x $15.77=$2.37.
So, the amount of tip you are going to leave is $2.37.

This makes the total cost of your meal (to write on your charge slip or other payment)

$15.77 + $2.37 = $18.14

$18.14 is your answer

5 0

3 years ago

The braking distance, in feet of a car a Travling at v miles per hour is given.

irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

The braking distance at 25 mph, is approximately 63.7 ft.

The braking distance at 55 mph, is approximately 298.35 ft.

The braking distance at 85 mph, is approximately 708.92 ft.

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

$D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.$

At 25 mph, the braking distance is approximately 63.7 ft.

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945 ft.s

$D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.$

At 55 mph, the braking distance is approximately 298.35 ft.

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

$D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.$

At 85 mph, the braking distance is approximately 708.92 ft.

b. The speed of the car when the braking distance is 450 feet is given as follows;

$450 = 2.6 + \dfrac{v^2}{22}$

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ 98.211 ft./s

Learn more here:

brainly.com/question/18591940

8 0

2 years ago

300 + 40 + 7/10 + 5/100 + 3/1000

Zielflug [23.3K]

Answer:1 5/10

Step-by-step explanation:

300 + 40 = 340 + 7/10 + 5/100 turn simplify it to 7/10 + 5/10 + 3/10 =15/10 = 1 5/0

5 0

3 years ago

Read 2 more answers

Help me solve this please!!

AVprozaik [17]

Answer:

Q 1. 8 yds Q2. 12 ft :)

Step-by-step explanation:

I got this right on my test so it should be the same.

8 0

3 years ago

Read 2 more answers

Simplify the following expression. 1/4 (24-16x) a. 6+4x b. 6+4 c. 6-4x d. 6-4

adoni [48]

Answer is 6-4x

1/4 evaluates to 1/4

Multiply x and 16

Multiply x and 1

after you have the answer it should come out to 24-16x then multiply 1/4 * 24-16x

1/4 *24=6

1/4*(24-16*x) evaluates to 6-4x

5 0

3 years ago

Read 2 more answers

Please help!!!!!!!!!!!!!!!!!!!!!!​

Please help!!!!!!!!!!!!!!!!!!!!!!