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3 years ago

12.5 of what number is 150

Mathematics

2 answers:

faust18 [17]3 years ago

5 0

Answer:

1200

Step-by-step explanation

1,200 x .125 = 150 is the correct form.

Y_Kistochka [10]3 years ago

4 0

Answer: 1,200

Step-by-step explanation:

1,200 x .125 = 150

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In the case of normally distributed classes, discriminant functions are linear (straight lines, planes, and hyperplanes for two-

PIT_PIT [208]

Answer:

True

Step-by-step explanation:

When covariance matrices of corresponding class are identical and diagonal matrix and their class probability is same then the class is normally distributed and its discriminant functions are linear.

3 0

3 years ago

How much elastic energy is stored in a slingshot that has a spring constant of 300 N/m and is stretched by 0.45m?

vagabundo [1.1K]

Answer:

E = 30.37 J

Step-by-step explanation:

Given that,

The spring constant of the spring, k = 300 N/m

The spring is stretched by 0.45 m, x = 0.45 m

We need to find the elastic energy stored in the spring. The formula for the elastic energy is given by :

$E=\dfrac{1}{2}kx^2\\\\=\dfrac{1}{2}\times 300\times (0.45)^2\\\\=30.37\ J$

So, the required elastic energy is equal to 30.37 J.

7 0

3 years ago

Plz answer it the last question

Liono4ka [1.6K]

Part A
36x48x18
Part B
12x48x18
100% correct

3 0

3 years ago

12.5% of what number is 24? Please help and show work

Vesnalui [34]

$12,5\%*x=24 \\ 0,125x=24 \ \ \ /:0,125\\ x=192$
As we all know:
$1\%= \frac{1}{100} \ \ \ therefore \ \ 12,5\%= \frac{125}{1000}$

3 0

3 years ago

Last year, Kevin had 20,000 to invest. He invested some of it in an account that paid 6% simple interest per year, and he invest

tester [92]

$13,000 was invested at 6% whereas $7,000 was invested at 10% using simple interest approach

What is simple interest?

Simple interest is determined as the amount invested multiplied by the interest rate and the number of years that investment lasts.

I=PRT

I=interest

P=principal

R=rate of return

T=time

Let X be the amount invested at 6%

I at 6%=6%*X*1

I=0.06X

The amount invested at 10% is 20,000-X

total interest=0.06X+0.10*(20000-X)

total interest=1,480

1480=0.06X+0.10*(20000-X)

1480=0.06X+2000-0.10X

1480-2000=0.06X-0.10X

-520=-0.04X

X=-520/-0.04

X=13,000

13,000 was invested at 6%

amount invested at 10%=20,000-X

amount invested at 10%=20,000-13,000

amount invested at 10%=7,000

Find out more about simple interest on:brainly.com/question/20690803

#SPJ1

4 0

2 years ago