To find the missing dimension you will use the formula for finding the volume of a prism and solve for the missing dimension. In this case 2ft is how deep the pool is and you will solve for the width of the pool.

V = Bh, where B is the area of the base. In this case, use the area of a trapezoid formula.

286 = 1/2h(8 +13)2
286 = 21h
21 21
h = 13.6

The width of the wading pool is approximately 13.6 feet.

5 0

3 years ago

Calculate the product of 8/15, 6/5, and 1/3.

Mariulka [41]

$\frac{8}{15} * \frac{6}{5} * \frac{1}{3}$

First, I would multiply the last two fractions because they're smaller and easier to work with:

$\frac{8}{15} * \frac{6}{5} * \frac{1}{3} = \frac{8}{15} * \frac{6}{15}$

Now that we've simplified it, we could multiply these terms and simplify. An easier method, however, would be to cancel out any common factors among the numerators and denominators before multiplying:

$\frac{8}{15} * \frac{6}{15} = \frac{8}{5} * \frac{2}{15}$

We can now multiply these terms:

$\frac{8}{5} * \frac{2}{15} = \frac{16}{75}$

The product of 8/15, 6/5, and 1/3 is B, 16/75.

5 0

3 years ago

A circle is drawn on the coordinate plane. It has a center at (2, 1) and passes through the point (2, 5). What is the approximat

ArbitrLikvidat [17]

First we need to find the radius. Using Pythagorean theorem we can find the radius which is the distance between the center and any point along the circle:

r=((5-1)^2+(2-2)^2)^(1/2)

r=(4^2-0^2)^(1/2)

r=4 units.

Circumference=2pr so our circumference is 8p units^2

Approximately 25.13 u^2

8 0

3 years ago