What is the prime factorization if 6400 using exponents

Mathematics

1 answer:

katovenus [111]4 years ago

5 0

So prime factorization is as it seems, finding the prime factors for a number. With this number, break it down as such:

$\underbrace{6400}_{\underbrace{64}_{\underbrace{8}_{\underbrace{4}_{\boxed{2*2}} \boxed{2}}*\underbrace{8}_{\underbrace{4}_{\boxed{2*2}}\boxed{2}}}*\underbrace{100}_{\underbrace{10}_{\boxed{5*2}}*\underbrace{10}_{\boxed{5*2}}}}$

<u>Looking at our factors, the prime factorization of 6400 is $2^8*5^2$ </u>

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Acrosonic's production department estimates that the total cost (in dollars) incurred in manufacturing x ElectroStat speaker sys

il63 [147K]

Answer:

a) $P(x)=-0.042x^2+530x-18000$

b) $P'(x)=-0.084x+530$

$P'(4000)=194$

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Step-by-step explanation:

We know that Revenue is our total income and cost is our total cost. Thus, profit is what's left after cost is subtracted from Income (revenue). Thus, we can say:

P(x) = R(x) - C(x)

Finding Profit Function (P(x)):

$P(x) = R(x) - C(x)\\P(x) = -0.042x^2+800x-(270x+18000)\\P(x)=-0.042x^2+800x-270x-18000\\P(x)=-0.042x^2+530x-18000$

This is the profit function.

The marginal profit is the profit earned when ONE ADDITIONAL UNIT of the product is sold. This is basically the rate of change of profit per unit. We find this by finding the DERIVATIVE of the Profit Function.

Remember the power rule for differentiation shown below:

$\frac{d}{dx}(x^n)=nx^{n-1}$