Answer:
Yes
Step-by-step explanation:
Yes it is
No 1 is correct
No 2 is correct
No 3 is correct
No 4 is correct
and what i mean by correct is you answered it correct
I hope this helps you :)
Solve for x over the real numbers:
3 x^2 + 5 x + 1 = 0
Hint: | Using the quadratic formula, solve for x.
x = (-5 ± sqrt(5^2 - 4×3))/(2×3) = (-5 ± sqrt(25 - 12))/6 = (-5 ± sqrt(13))/6:
Answer: x = (-5 + sqrt(13))/6 or x = (-5 - sqrt(13))/6
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<span>=<span><span><span><span><span>(3)</span><span>(x)</span></span>+<span><span>(3)</span><span>(4)</span></span></span>+<span><span>(2)</span><span>(<span>5x</span>)</span></span></span>+<span><span>(2)</span><span>(2)
</span></span></span></span><span>=<span><span><span><span>3x</span>+12</span>+<span>10x</span></span>+<span>4
</span></span></span><span>=<span><span><span><span>3x</span>+12</span>+<span>10x</span></span>+4
</span></span><span>=<span><span>(<span><span>3x</span>+<span>10x</span></span>)</span>+<span>(<span>12+4</span>)
</span></span></span><span>=<span><span>13x</span>+<span>16
Answer = </span></span></span><span>13x</span>+<span>16
(hope this helps)</span>
Answer:
-21.6
Step-by-step explanation:
-5.4
x 4 4x 4=16 so you carry the one to 5x4= 20 + 1 that was carried
-------- keep it negative
-21.6
