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Vladimir [108]
2 years ago
8

25 POINTS HELP NOWW

Mathematics
2 answers:
Olin [163]2 years ago
7 0

Answer:

i dont know math stinks

Step-by-step explanation:

Kruka [31]2 years ago
4 0

Answer:

I guess the answers in the photo?

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What is the value of x
Ainat [17]

Answer:

16

Step-by-step explanation:

(3x +3) + (5x-2) + (3x+3) =180

3x +3 + 5x-2 + 3x+3 =180

11x +4=180

11x =180-4

11x=176

x=176/11

x= 16

4 0
2 years ago
Turn these phrases into algebraic expressions (PLEASE HELP)
Aleks [24]
2x-7
7x+2
x-9
4x+9
4x-9
x/4
8 0
2 years ago
Read 2 more answers
What is -0.18 as a fraction in simplest form.
Radda [10]
The answer is, 9/50
0.18 = 0.18/1
0.18/1 x 100/100 = 18/100
18/100 divided by 2/2 = 9/50
In conclusion the answer is 9/50.
Hopefully that helped! :)
3 0
3 years ago
Find the equation of a circle with a center at (7,2) and a point on the circle at (2,5)?
monitta

Answer:

(x-7)^2+(y-2)^2=34

Step-by-step explanation:

We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).

First, recall that the equation of a circle is given by:

(x-h)^2+(y-k)^2=r^2

Where (<em>h, k</em>) is the center and <em>r</em> is the radius.

Since our center is at (7, 2), <em>h</em> = 7 and <em>k</em> = 2. Substitute:

(x-7)^2+(y-2)^2=r^2

Next, the since a point on the circle is (2, 5), <em>y</em> = 5 when <em>x</em> = 2. Substitute:

(2-7)^2+(5-2)^2=r^2

Solve for <em>r: </em>

<em />(-5)^2+(3)^2=r^2<em />

Simplify. Thus:

25+9=r^2

Finally, add:

r^2=34

We don't need to take the square root of both sides, as we will have the square it again anyways.

Therefore, our equation is:

(x-7)^2+(y-2)^2=34

4 0
2 years ago
Help please jggvnhujff
saveliy_v [14]

Answer:

Step-by-step explanation:

<u><em>8).</em></u>  \left \{ {{4x+3y=1} \atop {x+y=2}} \right.

<em>(2)</em> × [ - 3 ]

4x + 3y = 1 ........ <em>(3)</em>

- 3x - 3y = - 6 .... <em>(4)</em>

<em>(3)</em> + <em>(4)</em>

x = - 5

- 5 + y = 2 ⇒ y = 7

<em>( - 5 , 7 )</em>

<u><em>9).</em></u> \left \{ {{-9x+3y=18} \atop {2x+y=-4}} \right.

<em>(1)</em> ÷ [- 3]

3x - y = - 6  ......... <em>(3)</em>

2x + y = - 4 ........ <em>(4)</em>

<em>(3)</em> + <em>(4)</em>

5x = - 10 ⇒ x = - 2

2(- 2) + y = - 4 ⇒ y = 0

<em>(- 2, 0)</em>

<u><em>10).</em></u> \left \{ {{x-2y=14} \atop {10x-6y=0}} \right.

<em>(2)</em> ÷ 10

x - 0.6y = 0 ⇒ x = 0.6y -----> <em>(1)</em>

0.6y - 2y = 14

- 1.4y = 14

y = - 10

x - 2(- 10) = 14 ⇒ x = - 6

<em>(- 6, - 10)</em>

Now is your turn, you can do it!!

3 0
3 years ago
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