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Oliga [24]
3 years ago
14

Tia performed an experiment where she flipped a coin 200 times. The coin landed heads up 92 times and tails up 108 times. Which

statement about this experiment is true?
The ratio  represents the experimental probability of the coin landing heads up in this experiment.

The ratio  represents the number of trials in this experiment.

The ratio  represents the theoretical probability of the coin landing heads up in this experiment.

The ratio  represents the number of occurrences of the coin landing heads up in this experiment.
Mathematics
2 answers:
11111nata11111 [884]3 years ago
4 0

only the first statement is true - it is the experimental probability. the rest is incorrect: the ratio is not the number of trials; the theoretical probability should be 0.5 (for unbiased coins); ratio never represents a number of occurences.

lesya692 [45]3 years ago
4 0

Answer:

The correct option is 1.

Step-by-step explanation:

Total number of times she flipped a coin = 200

Total number of heads in the experiment = 92

Total number of tails in the experiment = 108

Theoretical probability of the coin landing heads up in this experiment is 0.5.

In the above experiment, the probability of the coin landing heads up is

P(H)=\frac{92}{200}=0.46

In the above experiment, the probability of the coin landing tails up is

P(T)=\frac{108}{200}=0.54

The ratio  represents the experimental probability of the coin landing heads up in this experiment.

Therefore the correct option is 1.

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Klio2033 [76]

Answer:

y

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
one number is equal to the square of another. find the numbers if both are positive and their sum is 1122
statuscvo [17]

Answer:

One number is 561

The other number is 23.6854

Step-by-step explanation:

x = y^2                One number = the square of another

x + y^2 = 1122     The sum of the two numbers is 1122

Substitute y^2 in for x on the second equation.

y^2 + y^2 = 1122    Combine like terms on the left

2y^2 = 1122            Divide by 2

y^2 = 1122/2

y^2 = 561                Take the square root of both sides.

y = 23.6854            

x = y^2

x = 561

y^2 = 561


4 0
3 years ago
Let C(n, k) = the number of k-membered subsets of an n-membered set. Find (a) C(6, k) for k = 0,1,2,...,6 (b) C(7, k) for k = 0,
vladimir1956 [14]

Answer:

(a) C(6,0) = 1, C(6,1) = 6, C(6,2) = 15, C(6,3) = 20, C(6,4) = 15, C(6,5) = 6, C(6,6) = 1.

(b) C(7,0) = 1, C(7,1) = 7, C(7,2) = 21, C(7,3) = 35, C(7,4) = 35, C(7,5) = 21, C(7,6) = 7, C(7,7)=1.

Step-by-step explanation:

In this exercise we only need to recall the formula for C(n,k):

C(n,k) = \frac{n!}{k!(n-k)!}

where the symbol n! is the factorial and means

n! = 1\cdot 2\cdot 3\cdot 4\cdtos (n-1)\cdot n.

By convention 0!=1. The most important property of the factorial is n!=(n-1)!\cdot n, for example 3!=1*2*3=6.

(a) The explanations to the solutions is just the calculations.

  • C(6,0) = \frac{6!}{0!(6-0)!} = \frac{6!}{6!} = 1
  • C(6,1) = \frac{6!}{1!(6-1)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6
  • C(6,2) = \frac{6!}{2!(6-2)!} = \frac{6!}{2\cdot 4!} = \frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15
  • C(6,3) = \frac{6!}{3!(6-3)!} = \frac{6!}{3!\cdot 3!} = \frac{5!\cdot 6}{6\cdot 6} = \frac{5!}{6} = \frac{120}{6} = 20
  • C(6,4) = \frac{6!}{4!(6-4)!} = \frac{6!}{4!\cdot 2!} = frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15
  • C(6,5) = \frac{6!}{5!(6-5)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6
  • C(6,6) = \frac{6!}{6!(6-6)!} = \frac{6!}{6!} = 1.

(b) The explanations to the solutions is just the calculations.

  • C(7,0) = \frac{7!}{0!(7-0)!} = \frac{7!}{7!} = 1
  • C(7,1) = \frac{7!}{1!(7-1)!} = \frac{7!}{6!} = \frac{6!\cdot 7}{6!} = 7
  • C(7,2) = \frac{7!}{2!(7-2)!} = \frac{7!}{2\cdot 5!} = \frac{6!\cdot 7}{2\cdot 5!} = \frac{5!\cdot 6\cdot 7}{2\cdot 5!} = \frac{6\cdot 7}{2} = 21
  • C(7,3) = \frac{7!}{3!(7-3)!} = \frac{7!}{3!\cdot 4!} = \frac{6!\cdot 7}{6\cdot 4!} = \frac{5!\cdot 6\cdot 7}{6\cdot 4!} = \frac{120\cdot 7}{24} = 35
  • C(7,4) = \frac{7!}{4!(7-4)!} = \frac{6!\cdot 7}{4!\cdot 3!} = frac{5!\cdot 6\cdot 7}{4!\cdot 6} = \frac{120\cdot 7}{24} = 35
  • C(7,5) = \frac{7!}{5!(7-2)!} = \frac{7!}{5!\cdot 2!} = 21
  • C(7,6) = \frac{7!}{6!(7-6)!} = \frac{7!}{6!} = \frac{6!\cdot 7}{6!} = 7
  • C(7,7) = \frac{7!}{7!(7-7)!} = \frac{7!}{7!} = 1

For all the calculations just recall that 4! =24 and 5!=120.

6 0
3 years ago
Write y=-3(x-7)^2-8 in vertex form
Veronika [31]

It's in the verex form:

f(x)+a(x-h)^2+k\\\\(h,\ k)-vertex

y=-3(x-7)^2-8\\\\(7,\ -8)-vertex

7 0
3 years ago
Read 2 more answers
(c) One lorry travels from your town to another town. The lorry reaches a top speed
Katen [24]

Answer:

The average speed is 24 km/h less than the top speed of the lorry.

Step-by-step explanation:

The top speed of the lorry is the highest speed reached during transit, while its average speed is the mean speed attained

Given:.

Top speed of the lorry = 90 km/h

Average speed of the lorry = 66 km/h

Then,

The difference between the speed reached = top speed - average speed

                                            = 90 - 66

                                            = 24 km/h

Therefore, the average speed is 24 km/h less than the top speed of the lorry.

8 0
3 years ago
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