Answer:
Correct option:
(B) <em>H₀</em>: <em>μ</em> = 2.40 vs. <em>Hₐ</em>: <em>μ</em> ≠ 2.40.
Step-by-step explanation:
The registrar of particular university in 1975 plans to look at records of students graduating last year to see if the mean GPA has changed from 2.40.
The registrar can use a single mean test to determine whether the mean has changed or not.
The hypothesis can be described as:
<em>H₀</em>: The mean GPA is 2.40, i.e. <em>μ</em> = 2.40.
<em>Hₐ</em>: The mean GPA is different from 2.40, i.e. <em>μ</em> ≠ 2.40.
To perform the test the registrar can either use a <em>z</em>-distribution or a <em>t</em>-distribution.
If the data provided gives some insight about the population standard deviation and the sample selected is quite large then the <em>z</em>-distribution can be used.
Otherwise it is wiser to use a <em>t</em>-distribution.
The decision rule is:
If the <em>p</em>-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.
Thus, the correct option is (B).
Answer:
fromfromfromfromfromfromfromfromfromfromfromfromfromfromfromfromfrom
Step-by-step explanation:
Answer:
The area of the rectangular coral = 2,976 ft²
Step-by-step explanation:
Bryce has 220 ft of fencing to fence a rectangular coral.
Let the dimensions of the corral be x ft. × y ft.
One side of the coral is 48 ft. long
A rectangle has 4 sides, with each of the two opposite sides with the same dimension. Hence, the perimeter of the rectangular coral = 2(x + y) = 2x + 2y.
Total length of material for fencing = 220 ft.
Hence the perimeter of the reef = 220 ft.
2x + 2y = 220
And one length of the rectangular coral = x = 48 ft.
We can solve for the remaining dimension of the rectangular coral this way.
2(48) + 2y = 220
2y = 220 - 96 = 124
y = (124/2) = 62 ft.
Hence, the area of the rectangular coral = xy = 48 × 62 = 2,976 ft²
Hope this Helps!!!
Letter B. X is a vertical angle, and so is F. Vertical angles are all congruent.
Any value of y, except when y = -4.9, will make the expression equal to 2.45.