How to get answer for number 1: | 4+2i |
How to get answer for number 2: | 5-i |
Number 3 how to get answer: | -3i |
![\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=0,\:b=-3\\=\sqrt{0^2+\left(-3\right)^2}\\Refine\\=\sqrt{9}\\\sqrt{9}\\\mathrm{Factor\:the\:number:\:}\:9=3^2\\=\sqrt{3^2}\\\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a\\\sqrt{3^2}=3\\= 3](https://tex.z-dn.net/?f=%5Cleft%7Ca%2Bbi%5Cright%7C%5C%3A%3D%5Csqrt%7B%5Cleft%28a%2Bbi%5Cright%29%5Cleft%28a-bi%5Cright%29%7D%3D%5Csqrt%7Ba%5E2%2Bb%5E2%7D%5C%5C%5Cmathrm%7BWith%5C%3A%7Da%3D0%2C%5C%3Ab%3D-3%5C%5C%3D%5Csqrt%7B0%5E2%2B%5Cleft%28-3%5Cright%29%5E2%7D%5C%5CRefine%5C%5C%3D%5Csqrt%7B9%7D%5C%5C%5Csqrt%7B9%7D%5C%5C%5Cmathrm%7BFactor%5C%3Athe%5C%3Anumber%3A%5C%3A%7D%5C%3A9%3D3%5E2%5C%5C%3D%5Csqrt%7B3%5E2%7D%5C%5C%5Cmathrm%7BApply%5C%3Aradical%5C%3Arule%7D%3A%5Cquad%20%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da%5C%5C%5Csqrt%7B3%5E2%7D%3D3%5C%5C%3D%203)
Answer: where's the question
Step-by-step explanation:
The answer would be 4c^2+8c+3
The arrow stands for squared off you didn’t already know but these are very easy to solve because you just multiply it out
Step-by-step explanation:
A/2 = 4
A = 4 x 2
A = 8
I think this should be the answer
The value of the given expression after addition is 199 and this can not written as a mixed number in the simplest form.
According to the question,
We have the following expression:
212+(-13)
Now, we know that the multiplication of one negative and one positive integers is always positive.
So, we have the following expression:
212-13
199
Now, this number is whole number and it can not be written as a mixed number. It could only have been written as a mixed number when the result would have been in a fraction.
Hence, the value of the given expression after addition is 199 and this can not written as a mixed number in the simplest form.
To know more about addition here
brainly.com/question/19867930
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