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liraira [26]
3 years ago
9

Find the value of root 121 + 3 over root 125

Mathematics
2 answers:
NemiM [27]3 years ago
7 0

Answer:

\mathrm{Decimal:\quad }\:1.25219\\\frac{14\sqrt{5}}{25}

Step-by-step explanation:

\frac{\sqrt{121}+3}{\sqrt{125}}\\\sqrt{125}=5\sqrt{5}\\=\frac{\sqrt{121}+3}{5\sqrt{5}}\\\sqrt{121}=11\\=\frac{11+3}{5\sqrt{5}}\\\mathrm{Add\:the\:numbers:}\:11+3=14\\=\frac{14}{5\sqrt{5}}\\\mathrm{Rationalize\:}\frac{14}{5\sqrt{5}}:\quad \frac{14\sqrt{5}}{25}\\=\frac{14\sqrt{5}}{25}

Mice21 [21]3 years ago
7 0

Answer

root of 121 is 11 \sqrt{121} =11

then you add 11 and 3 which equals to 14 11+3=14

then you do 14 over root 125 \frac{14}{\sqrt{125} }

which is 1.25219

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Answer:

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or if you meant 80 +  [ 8*4 /  2], then 80 +  [ 8*4 /  2] = 96

Step-by-step explanation:

Evalute the expression. 80 + (8x4) divided by 2

so do you mean

the whole expression 80 + (8x4)   is  over  2 ?

If so then:

evaluate  8x4  =  8 * 4 = 32.

so   we have 80 + (8x4)   is  over  2  =  (80 + 32)/2 = 112/2 = 56

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3 years ago
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Step-by-step explanation:

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