Question

Find the value of root 121 + 3 over root 125

Answer 1

Answer:

$\mathrm{Decimal:\quad }\:1.25219\\\frac{14\sqrt{5}}{25}$

Step-by-step explanation:

$\frac{\sqrt{121}+3}{\sqrt{125}}\\\sqrt{125}=5\sqrt{5}\\=\frac{\sqrt{121}+3}{5\sqrt{5}}\\\sqrt{121}=11\\=\frac{11+3}{5\sqrt{5}}\\\mathrm{Add\:the\:numbers:}\:11+3=14\\=\frac{14}{5\sqrt{5}}\\\mathrm{Rationalize\:}\frac{14}{5\sqrt{5}}:\quad \frac{14\sqrt{5}}{25}\\=\frac{14\sqrt{5}}{25}$

Answer 2

Answer

root of 121 is 11 $\sqrt{121}$ =11

then you add 11 and 3 which equals to 14 11+3=14

then you do 14 over root 125 $\frac{14}{\sqrt{125} }$

which is 1.25219