It is 2,56 i think but i dont completely know thoe
Answer:
<h2>Sorry mate I am not able to understand ur question ❓❓❓❓ . sorry mate next time I can give u the answer.</h2>
Answer:
37.5 acres.
Step-by-step explanation:
Fraction of his land where vegetables are grown
= 1 - 1/3 - 2/3 *3/5
(after taking away 1/3 we get 2/3 and the farmer uses 3/5 of this 2/3 to grow Maize.
= 1 - 1/3 - 6/15 LCD of 3 and 15= 15 so we write:
= 1 - 5/15 - 6/15
= 1 - (5+6)/16
= 1 - 11/15
= 4/15.
4 /15 is equivalent to 10 acres
so total area (= 1) = 10 / 4/15 Invert the 4/15 and multiply:
= 10 * 15/4
= 150/4
= 37.5 acres.
Answer: (B)
Explanation: If you are unsure about where to start, you could always plot some numbers down until you see a general pattern.
But a more intuitive way is to determine what happens during each transformation.
A regular y = |x| will have its vertex at the origin, because nothing is changed for a y = |x| graph. We have a ray that is reflected at the origin about the y-axis.
Now, let's explore the different transformations for an absolute value graph by taking a y = |x + h| graph.
What happens to the graph?
Well, we have shifted the graph -h units, just like a normal trigonometric, linear, or even parabolic graph. That is, we have shifted the graph h units to its negative side (to the left).
What about the y = |x| + h graph?
Well, like a parabola, we shift it h units upwards, and if h is negative, we shift it h units downwards.
So, if you understand what each transformation does, then you would be able to identify the changes in the shape's location.
Answer:
119.05°
Step-by-step explanation:
In general, the angle is given by ...
θ = arctan(y/x)
Here, that becomes ...
θ = arctan(9/-5) ≈ 119.05°
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<em>Comment on using a calculator</em>
If you use the ATAN2( ) function of a graphing calculator or spreadsheet, it will give you the angle in the proper quadrant. If you use the arctangent function (tan⁻¹) of a typical scientific calculator, it will give you a 4th-quadrant angle when the ratio is negative. You must recognize that the desired 2nd-quadrant angle is 180° more than that.
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It may help you to consider looking at the "reference angle." In this geometry, it is the angle between the vector v and the -x axis. The coordinates tell you the lengths of the sides of the triangle vector v forms with the -x axis and a vertical line from that axis to the tip of the vector. Then the trig ratio you're interested in is ...
Tan = Opposite/Adjacent = |y|/|x|
This is the tangent of the reference angle, which will be ...
θ = arctan(|y| / |x|) = arctan(9/5) ≈ 60.95°
You can see from your diagram that the angle CCW from the +x axis will be the supplement of this value, 180° -60.95° = 119.05°.
