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3 years ago

Hello everyone can you answer this for me? What is A in the equation attached? Please and thank you.

Mathematics

2 answers:

lapo4ka [179]3 years ago

7 0

Answer:

a = 6

Step-by-step explanation:

Hello!

Solve:

4(3a - 4) = 56
3a - 4 = 14 (factoring out 4)
3a = 18 (adding 4 to both sides)
a = 6 (dividing by 3)

Another way:

4(3a - 4) = 56
12a - 16 = 56 (distributive property)
12a = 72 (moving like terms)
a = 6 (dividing by 12)

Distributive Property of Multiplication:

The process of distributing the outside factor to the terms in the parenthesis.

Example:

$4(3a - 4)\\\\4(3a) - 4(4)\\\\12a - 16$

11Alexandr11 [23.1K]3 years ago

6 0

A=6 bc you multiply 6 by 3 then get 18 which u then subtract by 4 which will get you 14 then multiply that by 4 and that equals 56

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Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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lawyer [7]

Complete Question:

There are 8 rows and 8 columns, or 64 squares on a chessboard.

Suppose you place 1 penny on Row 1 Column A,

2 pennies on Row 1 Column B,

4 pennies on Row 1 Column C, and so on …

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Answer:

255 in the first row

18,446,744,073,709,551,615 in the entire board

Step-by-step explanation:

Given

$Rows = 8$

$Columns = 8$

Solving (a): Number of pennies in first row

The question is an illustration of geometric sequence which follows

$1,2,4....$

Where

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$r = \frac{T_2}{T_1} = \frac{4}{2} = 2$

The number of pennies in the first row will be calculated using sum of n terms of a GP.

$S_n = \frac{a(r^n - 1)}{n - 1}$

Since, the first row has 8 columns, then

$n = 8$

Substitute 8 for n, 2 for r and 1 for a in $S_n = \frac{a(r^n - 1)}{r - 1}$

$S_8 = \frac{1 * (2^8 - 1)}{2 - 1}$

$S_8 = \frac{1 * (256 - 1)}{1}$

$S_8 = \frac{1 * 255}{1}$

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So:

$n = 64$

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$S_{64} = \frac{1 * (2^{64} - 1)}{2 -1}$

$S_{64} = \frac{(2^{64} - 1)}{1}$

$S_{64} = \frac{(18,446,744,073,709,551,616 - 1)}{1}$

$S_{64} = \frac{18,446,744,073,709,551,615}{1}$

$S_{64} = 18,446,744,073,709,551,615$

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