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emmasim [6.3K]
2 years ago
14

HELP WILL GIVE 50+ POINTS TO THE FIRST PERSON TO ANSWER PLZ HELP EXPLAIN IT ALL!!!!!!!!

Mathematics
1 answer:
Bogdan [553]2 years ago
3 0
No picture of the question
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Part 3 - Discussion/Explanation Question
SpyIntel [72]

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

\frac{1}{x - 5}

Set the expression in the denominator equal to 0, because you can't divide by 0.

x - 5 = 0

x = 5

So the vertical asymptote is x=5.

Disclaimer if you see something like this

\frac{(x - 5)(x + 3)}{(x - 5)}

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

\frac{1}{x}

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

a \times  {x}^{0}

For example,

1 = 1 \times  {x}^{0}

2 =  2 \times {x}^{0}

And so on,

and

x =  {x}^{1}

So our equation is basically

\frac{1 \times  {x}^{0} }{ {x}^{1} }

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

\frac{3 {x}^{2} }{ {x}^{2}  + 1}

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

x =  \frac{3}{1}

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

8 0
2 years ago
Between the first and second year of existence of a community service organization, the membership of the organization grew by 1
Marianna [84]

Answer:

i don't know the answer sorry

7 0
2 years ago
I need help solving ​
vaieri [72.5K]

Answer:

well if you're looking for angles then

angle ADB = 30°

angle CBD = 80°

angle CDB = 120°

but they asked to classify triangle ADC ,whose measurements are 90° , 40° and 50° ...so of they're asking what type of triangle then it is a right angled triangle.

5 0
2 years ago
Read 2 more answers
given that (-3,-5) and (-1,-4) are points on the same line, find a point slope form of the equation for this line
posledela
The answer to the question

3 0
3 years ago
If p =-2 ,q= -1 and r=3 <br>find the value of . -<br>(1), p ²+ q²- r²​
sammy [17]

Answer:

Step-by-step explanation:

(-2)^{2} + (-1)^{2} - (3^{2} )\\4 + 1 -9\\-4

8 0
2 years ago
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