What is 67/100 as a decimal representation and a percent representation
2 answers:
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Hey Jackson!
-4x + 3y = 3
y = 2x + 1
Ok so what we need to do is solving y= 2x + 1 for y.
So let's start by using the substitution method :)
Substitute 2x + 1 for y in -4x + 3y = 3
-4x+ 3y = 3
-4x + 3(2x + 1) = 3
-4x + (3)(2x) + (3)(1) = 3
-4x + 6x + 3 = 3
2x + 3 = 3
Subtract 3 on both sides
2x + 3 - 3 = 3 - 3
2x = 0
x = 0/2
x = 0
So now since we find the number for x, we gonna use it to help us find the value for y.
To find y, we need to substitute 0 for x in y = 2x + 1
y = 2x + 1
y = 2(0) + 1
y = 0 + 1
y = 1
Thus,
The answer is: y = 1 and x = 0
How to graph?
You need to go on the thing where they put the numbers. y is located on top which has the positive numbers. So when you get there, make a line that comes from the top right side all the way to the bottom left sides. Remember that y = 1 so the line must pass through 1
I am not good with explanation. So I'll leave the graph down below then you'll see what I am talking about :)
Let me know if you have any questions. As always, it is my pleasure to help students like you!
-4x + 3y = 3
y = 2x + 1
Ok so what we need to do is solving y= 2x + 1 for y.
So let's start by using the substitution method :)
Substitute 2x + 1 for y in -4x + 3y = 3
-4x+ 3y = 3
-4x + 3(2x + 1) = 3
-4x + (3)(2x) + (3)(1) = 3
-4x + 6x + 3 = 3
2x + 3 = 3
Subtract 3 on both sides
2x + 3 - 3 = 3 - 3
2x = 0
x = 0/2
x = 0
So now since we find the number for x, we gonna use it to help us find the value for y.
To find y, we need to substitute 0 for x in y = 2x + 1
y = 2x + 1
y = 2(0) + 1
y = 0 + 1
y = 1
Thus,
The answer is: y = 1 and x = 0
How to graph?
You need to go on the thing where they put the numbers. y is located on top which has the positive numbers. So when you get there, make a line that comes from the top right side all the way to the bottom left sides. Remember that y = 1 so the line must pass through 1
I am not good with explanation. So I'll leave the graph down below then you'll see what I am talking about :)
Let me know if you have any questions. As always, it is my pleasure to help students like you!
Answer:
see attached
Step-by-step explanation:
The Pythagorean theorem can be used to find the hypotenuse associated with each pair of legs. That tells you ...
c² = a² +b² . . . . . legs a, b; hypotenuse c
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<h3>alternate form of Pythagorean theorem</h3>For the purpose of this problem, it is convenient to consider a slightly different form of the equation.
For legs √a and √b, the hypotenuse √c is given by ...
(√c)² = (√a)² +(√b)²
c = a +b
That is ...
legs √a, √b ⇒ hypotenuse √(a+b)
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<h3>application to this problem</h3>Since the legs are (mostly) given in terms of square roots, the value under the radical for the hypotenuse is simply the sum of those:
legs: √1, √2 ⇒ hypotenuse √(1+2) = √3
legs: √2, √3 ⇒ hypotenuse √(2+3) = √5
legs: √5, √3 ⇒ hypotenuse √(5+3) = √8
legs: √5, √1 ⇒ hypotenuse √(5+1) = √6
_____
<em>Additional comment</em>
You may not see the leg lengths given as square roots very often. This is a rather unusual set of problems for hypotenuse length.
