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3 years ago

Determine if the ordered pair (-1,-5) is a solution to the inequality ys. --x-1

Mathematics

1 answer:

olga55 [171]3 years ago

4 0

9514 1404 393

Answer:

yes, because (-1, -5) is below the line

Step-by-step explanation:

You can put the values into the inequality and see if it is true.

y ≤ -x -1

-5 ≤ -(-1) -1

-5 ≤ 0 . . . . . . . true

The given point is a solution in the shaded area below the line.

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ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions

liq [111]

Answer:

The function has two real roots and crosses the x-axis in two places.

The solutions of the given function are

x = (-0.4495, 4.4495)

Step-by-step explanation:

The given quadratic equation is

$G(x) = -x^2 + 4x + 2$

A quadratic equation has always 2 solutions (roots) but the nature of solutions might be different depending upon the equation.

Recall that the general form of a quadratic equation is given by

$a^2 + bx + c$

Comparing the general form with the given quadratic equation, we get

$a = -1 \\\\b = 4\\\\c = 2$

The nature of the solutions can be found using

If $b^2- 4ac = 0$ then we get two real and equal solutions

If $b^2- 4ac > 0$ then we get two real and different solutions

If $b^2- 4ac < 0$ then we get two imaginary solutions

For the given case,

$b^2- 4ac \\\\(4)^2- 4(-1)(2) \\\\16 - (-8) \\\\16 + 8 \\\\24 \\\\$

Since 24 > 0

we got two real and different solutions which means that the function crosses the x-axis at two different places.

Therefore, the correct option is the last one.

The function has two real roots and crosses the x-axis in two places.

The solutions (roots) of the equation may be found by using the quadratic formula

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-(4)\pm\sqrt{(4)^2-4(-1)(2)}}{2(-1)} \\\\x=\frac{-4\pm\sqrt{(16 - (-8)}}{-2} \\\\x=\frac{-4\pm\sqrt{(24}}{-2} \\\\x=\frac{-4\pm 4.899}{-2} \\\\x=\frac{-4 + 4.899}{-2} \: and \: x=\frac{-4 - 4.899}{-2}\\\\x= -0.4495 \: and \: x = 4.4495 \\\\$

Therefore, the solutions of the given function are

x = (-0.4495, 4.4495)

A graph of the given function is also attached where you can see that the function crosses the x-axis at these two points.

6 0

3 years ago

HOW WOULD YOU DO THIS???

arlik [135]

Well to start off with, this is an intersecting angle. as you can see, on part is already at a 60 degree angle. each angle inside is an acute angle, but they are still equal to each other.

because of this, you have to look at the angle inside of this (the acute angle)

both X and Y would also be 60 degrees...

hope this helps!

4 0

4 years ago

Read 2 more answers

I thought this was much more easier for you! :)

monitta

Problem 1)

The base of the exponential is 12 which is also the base of the log as well. The only answer choice that has this is choice B.

======================================================================
Problem 2)

log(x) + log(y) - 2log(z)
log(x) + log(y) - log(z^2)
log(x*y) - log(z^2)
log[(x*y)/(z^2)]

Answer is choice D

======================================================================
Problem 3)

log[21/(x^2)]
log(21) - log(x^2)
log(21) - 2*log(x)

This matches with choice B

======================================================================
Problem 4)

Ln(63) = Ln(z) + Ln(7)
Ln(63)-Ln(7) = Ln(z)
Ln(63/7) = Ln(z)
Ln(9) = Ln(z)
z = 9

======================================================================
Problem 5)

Ln(5x-3) = 2
5x-3 = e^2
5x = e^2+3
x = (e^2+3)/5

This means choice A is the answer

4 0

3 years ago

Pls explain this to me I don't get it

WITCHER [35]

Answer:

u divide all numbers by 1000

Step-by-step explanation:

3 0

3 years ago

Han made some hot chocolate by mixing 4 cups of milk with 6 tablespoons of cocoa.

Genrish500 [490]

1.5 cups of cocoa for every 1 cup of milk

7 0

4 years ago