what is the equation of the line that is parallel to the line y- 1 = 4(x+3) and passes through the point (4,32)
1 answer:
Explanation:
y-1 = 4(x+3)
Put this into slope intercept form y=mx+b
y-1=4x+12
y =4x+13
the slope is 4
parallel lines have same slope so you want
equation for line with slope m=4
through (4,32)
y=4x+b using (4,32) for (x,y) solve for b
32=4(4)+b
32=16+b
16=b
your equation is
y = 4x + 16
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