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Brilliant_brown [7]
3 years ago
7

Please MY LAST 15 POINTS! What is the x-coordinate of point B? Write a decimal coordinate.

Mathematics
1 answer:
Murrr4er [49]3 years ago
4 0

Answer:

-1.5

Step-by-step explanation:

i hope this helps

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The linear combination method is applied to a system of equations as shown. 4(.25x + .5y = 3.75) → x + 2y = 15 (4x – 8y = 12) →
Ket [755]

Answer:

x+2y=12-------(1)

x-2y=3---------(2)

Adding equations 1 and 2

we get

2x=18

x=9

Equation 1

9+2y=15

2y=15-9

2y=6

y=3

The solution of the given system is x=9, y=3

Step-by-step explanation

6 0
3 years ago
What is 922/21 as a mixed number?
Fed [463]

Answer:

The answer is 43 and 19 over 21

Step-by-step explanation:

21 goes into 922 43 times. This giving you 903. 43 Will then be your Whole number. You the subtract 922 by 903, this giving you 19. 19 is going to be your numerator. Then you always keep the denomonator which is 21. This giving you 43 and 19 over 21

4 0
3 years ago
Someone help me with these two. I'll give you brainliest and 25 points!! MATHEMATICIANS OUT THERE HELP
mixer [17]
Hello LovingAngel!

To find the slope, you can use the formulas \frac{rise}{run} as well as \frac{y^2-y^1}{x^2 - x^1}. I am using the latter to calculate and ensuring my answer with the former. 

[Note: (x,y) is the format for ordered pairs]

First pair:  value 1:(1,5) and value 2:(2,8) 
\frac{y^2-y^1}{x^2 - x^1} -> \frac{8 - 5}{2 - 1} -> \frac{3}{1} or 3. 

The slope for (1,5) and (2,8) is 3(/1). 

Second pair: value 1: (3,1) value 2 (3,-1)

\frac{y^2-y^1}{x^2 - x^1} -> \frac{-1 - 1}{3 - 3} -> \frac{-2}{0}
Slope for the second pair is -2/0

Checking work with \frac{rise}{run}
1. Slope: 3/1, meaning rise (y) +3 and run (x) +1.  (1,5) -> (1+1,5 + 3) -> (2,8) ✔
2. Slope: -2/0, meaning rise (y) -2/drop (y) 2 and run 0. (3,1) -> (3 + 0, 1 + -2) -> (3,-1) <span>✔</span>

6 0
3 years ago
I need help n explainnnn please ​
kobusy [5.1K]

The Correct option is D). y=1x+1 And y=2x+2

Step-by-step explanation:

The equation of a line is given as y=mx+c.

where m=slope of line and c=y intercept

The slope of line is given as  m=\frac{(Y2-Y1)}{(X2-X1)}

Solving for Redline:

From the given graph, redline passes through (-1,0) and (0,1)

The slope of Redline is  m=\frac{(Y2-Y1)}{(X2-X1)}

The slope of Redline is  m=\frac{(1-0)}{(0-(-1))}

The slope of Redline is  m=(1)

And Y-intercept is 1

The equation of a Redline is given as y=1x+1

Solving for Blue-line:

From the given graph, Blue-line passes through (-1,0) and (0,2)

The slope of Blue-line is  m=\frac{(Y2-Y1)}{(X2-X1)}

The slope of Blue-line is  m=\frac{(2-0)}{(0-(-1))}

The slope of Blue-line is  m=(2)

And Y-intercept is 2

The equation of a Blue-line is given as y=2x+2

The Correct option is D). y=1x+1 And y=2x+2

7 0
3 years ago
Help big points, need quickly pls pls pls
Nezavi [6.7K]

Answer:

use photomath and if that dont work use m a t h w a y

Step-by-step explanation:

8 0
3 years ago
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