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Naddik [55]
3 years ago
13

g A test was conducted to determine if there is a difference between Canadian and American average heart rates. A group of 36 Ca

nadians and 34 Americans were randomly selected and their heart rates measured in beats per minute (bpm). The mean heart rate for Canadians was 68.5 and 70 for Americans. The pooled standard deviation of 2.0 beats/minute was calculated. Estimate a plausible range of differences between the mean heart rate of Canadians and Americans. What statistical procedure should be used to answer this research question
Mathematics
1 answer:
melisa1 [442]3 years ago
6 0

Answer:

The test statistic  | t |  =4.45

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the first sample size n₁ = 36

Given that the second sample size n₂ = 34

Mean of the first sample x₁⁻ = 68.5

Mean of the second sample x₂⁻ = 70

<u><em>Step(ii):-</em></u>

Test statistic

       t = \frac{x^{-} _{1}-x^{-} _{2}  }{\sqrt{S^{2} (\frac{1}{n_{1} }+\frac{1}{n_{2} }  } )}

     t = \frac{68.5-70}{\sqrt{2(\frac{1}{36}+\frac{1}{34} ) } }

    t = \frac{-1.5}{0.337} = -4.45

The test statistic  | t | = |-4.45| =4.45

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In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= root 2 cm.
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Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.

Let AD=x, Since given AB=3

                                     AD+DB=3

                                       x+DB = 3

                                        DB = 3-x

Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem

BC^{2} = DB^{2} +CD^{2}

BC^{2} = (3-x)^{2} +(\sqrt{2} )^{2}

BC^{2} =(3-x)^{2} +2

Since given AD=BC,let us plugin BC=x in above step.

x^{2} =(3-x)^{2} +2

x^{2} =9-6x+x^{2} +2

6x=11

x=\frac{11}{6}

Now we know AD=x=\frac{11}{6} and given CD=√2.

Let us apply Pythagoras theorem for ΔACD

AC^{2} =AD^{2} +DC^{2}

AC^{2} = (\frac{11}{6} )^{2} +(\sqrt{2} )^{2}

AC^{2} =\frac{193}{36}

AC=\sqrt{\frac{193}{36} } = 2.315cm

3 0
3 years ago
3/4w=9 what does w equal?
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3/4 w = 9

multiply by 4/3 on both sides

4/3 x 3/4 w = 9 x 4/3

w = 9 x 4/3

Simplify that

w = 3 x 4

w = 12

So your final answer is

\boxed{\bf{w=12}}
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Answer:

Equations::

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