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Vikentia [17]
3 years ago
10

Write a resonance form for pyrrole in which nitrogen has a formal charge of 1. Are comparable resonance forms possible for pyrid

ine
Chemistry
1 answer:
Svetach [21]3 years ago
3 0

Answer:

See explanation and image attached

Explanation:

Here attached are resonance forms of pyrrole and pyridine. The images were obtained from quora and researchgate respectively.

Now, we can see that in the resonance forms of pyrrole, the nitrogen atom in the heterocycle has a formal charge of +1. However, in the six membered pyridine hetrocycle, the nitrogen atom may have a formal charge of -1 or +1 as shown in the canonical structures attached. The structures in which nitrogen has a +1 formal charge in pyridine are comparable to structures obtained from pyrrole. These structures have less contribution to the structure of pyridine.

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A helium-filled balloon escapes a child's hand at sea level and 21.1 deg C. When it reaches an altitude of 3000 m, where the tem
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Answer:

Explanation:

Well use the combines gas law to evaluate this question;

P₁V₁/T₁ = P₂V₂/T₂     (Remember that at sea level the pressure is usually 1 atm)

1 * V₁ / 294.25 = 0.72 * V₂ / 277.95     (NB: Temperatures have to be in Kelvin)

V₁ / 294.25 * 277.95     = 0.72 V₂

0.945 V₁ = 0.72 V₂

0.945/0.72 V₁ = V₂

1.312 V₁ = V₂

The volume (V2) at 3000 m altitude will be <u>1.312 </u>bigger than the initial volume at sea level.

3 0
3 years ago
When Barium chloride is formed, what questions will the student need to know prior to making the formula???
guapka [62]

Answer:

Valency of the two elements

Explanation:

In order to correctly formularize the compound, the student needs to ask of the valences of the elements involved.

Chlorine has valency of -1, while Barium +2.

The exchange of valency gives the formula BaCl_{2}.

Another explanation is that Barium donates 2 electrons which the chlorine atoms accept, in order to form the covalent bond.

I hope this was helpful.

3 0
3 years ago
Which of the following is the correct model of C6H14?
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A. B. C.D.-allnswers 4 answers

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A 1.00 L volume of HCl reacted completely with 2.00 L of 1.50 M Ca(OH)2 according to the balanced chemical equation below. 2HCl
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The half-life for the radioactive decay of C-14 is 5730 years and is independent of the initial concentration. How long does it
DedPeter [7]

Answer:

It will take 2378 years for 25% of the C-14 atoms in a sample of the C-14 to decay.

Explanation:

Radioactive decays/reactions always follow a first order reaction dynamic.

Let the initial amount of C-14 atoms be A₀ and the amount of atoms at any time be A

The general expression for rate of reaction for a first order reaction is

(dA/dt) = -kA (Minus sign because it's a rate of reduction)

k = rate constant

(dA/dt) = -kA

(dA/A) = -kdt

 ∫ (dA/A) = -k ∫ dt 

Solving the two sides as definite integrals by integrating the left hand side from A₀ to A and the right hand side from 0 to t.

We get

In (A/A₀) = -kt

(A/A₀) = e⁻ᵏᵗ

A(t) = A₀ e⁻ᵏᵗ

Although, we can obtain k from the information on half life.

For a first order reaction, the rate constant (k) and the half life (T(1/2)) are related thus

T(1/2) = (In2)/k

T(1/2) = 5730 years

k = (In 2)/5730 = 0.000120968 = 0.000121 /year.

So, the amount of C-14 atoms left at any time is given as

A(t) = A₀ e⁻⁰•⁰⁰⁰¹²¹ᵗ

How long does it take for 25% of the C-14 atoms in a sample of the C-14 to decay?

When 25% of C-14 atoms in a sample decay, 75% of C-14 atoms in the sample remain.

Hence,

A(t) = 75%

A₀ = 100%

100 = 75 e⁻⁰•⁰⁰⁰¹²¹ᵗ

e⁻⁰•⁰⁰⁰¹²¹ᵗ = (75/100) = 0.75

In e⁻⁰•⁰⁰⁰¹²¹ᵗ = In 0.75 = - 0.28768

-0.000121t = -0.28768

t = (0.28768/0.000121) = 2,377.54 = 2378 years

Hope this Helps!!!

3 0
3 years ago
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