Question

Measurement of heat conductivity A metal panel of area A = 100 cm² and thickness Y = 0.5 cm was found to conduct heat at a rate of 3 W at steady state with temperatures To = 25 °C and T, = 30 °C imposed on the two main surfaces. What is the average thermal conductivity of the material at this temperature range?

Answer 1

Answer:

The average thermal conductivity of the material at this temperature range is 3*10^(-9) W/mK.

Explanation:

The heat flow through this area of the metal panel can be expressed as:

$q/A=-k\frac{(T_2-T_1)}{Y}$

being A the surface area, k the thermal conductivity, T2 and T1 the temperatures in each side and Y the thickness of the metal panel.

We have to rearrange the equation to clear k:

$k=\frac{-(q/A)*Y}{\Delta T} = \frac{-(3 W/100 cm2)*0.5cm}{5 ^\circ K}*(\frac{1m}{100cm} )^{3} \\\\k=\frac{0.015}{5*100^{3} }W/mK= 3*10^{-9}W/mK$

The average thermal conductivity of the material at this temperature range is 3*10^(-9) W/mK.