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creativ13 [48]
2 years ago
6

If you have an aqueous solution that contains 1.5 moles of hcl, how many moles of ions are in the solution? (a) 1.0, (b) 1.5, (c

) 2.0, (d) 2.5, (e) 3.if you have an aqueous solution that contains 1.5 moles of hcl, how many moles of ions are in the solution? (a) 1.0, (b) 1.5, (c) 2.0, (d) 2.5, (e) 3.

Chemistry
2 answers:
Daniel [21]2 years ago
8 0

The correct option is \boxed{\left( {\text{e}} \right)}. The number of moles of ion in the solution is \boxed{3\;{\text{moles}}}

Further Explanation:

An acid is a substance that has the ability to donate {{\text{H}}^+} ions or can accept electrons from the electron-rich species. The acids can be classified into two types as follows:

1. Strong acids

2. Weak acids

1. Strong acids:

The acids that undergo complete dissociation into its constituent ions when dissolved in water are known as strong acids. The pH value of strong acids is lower than pH value of weak acids. Examples of strong acids include HCl, {\text{HN}}{{\text{O}}_3} and {{\text{H}}_2}{\text{S}}{{\text{O}}_4}. The general dissociation reaction of a strong acid is as follows:

 {\text{HA}}+{{\text{H}}_2}{\text{O}}\to {{\text{H}}_3}{{\text{O}}^+}+{{\text{A}}^-}

Here, HA is a strong acid.

2. Weak acids:

The acids that undergo partial dissociation into its constituent ions when dissolved in water are known as weak acids. pH value of weak acids is higher than pH value of strong acids. Examples of weak acids include , {\text{C}}{{\text{H}}_3}{\text{COOH}}, HCOOH and HCN. The general dissociation reaction of a weak acid is as follows:

{\text{HB}} + {{\text{H}}_2}{\text{O}} \rightleftharpoons {{\text{H}}_3}{{\text{O}}^+} + {{\text{B}}^ -}

Here, HB is a weak acid.

HCl is a strong acid and therefore it dissociates completely into  {{\mathbf{H}}_{\mathbf{3}}}{{\mathbf{O}}^{\mathbf{+}}} and {\mathbf{C}}{{\mathbf{l}}^-} ions. The dissociation reaction of HCl is as follows:

{\text{HCl}}\left( g \right) + {{\text{H}}_2}{\text{O}}\left( l \right) \to {{\text{H}}_3}{{\text{O}}^+}\left( {aq} \right) + {\text{C}}{{\text{l}}^-}\left( {aq} \right)

The above chemical equation depicts that one mole of HCl dissociates to give one mole of {{\text{H}}_{\text{3}}}{{\text{O}}^+} ion and one {\text{C}}{{\text{l}}^-} mole of  ion. Therefore 1.5 mol of HCl will dissociate to give 1.5 mol of {{\text{H}}_{\text{3}}}{{\text{O}}^+} ions and  1.5 mol of {\text{C}}{{\text{l}}^-} ions.

The total number of moles of ions released from 1.5 mol of HCl in the aqueous solution is the sum of {{\text{H}}_{\text{3}}}{{\text{O}}^+} ions and {\text{C}}{{\text{l}}^-} ions.

\begin{gathered}{\text{Total moles of ions}} = {\text{ions of }}{{\text{H}}_{\text{3}}}{{\text{O}}^+} + {\text{ions of C}}{{\text{l}}^ - }\\= 1.5\;{\text{moles}} +1.5\;{\text{moles}} \\= {\text{3 moles}} \\ \end{gathered}

Hence, the correct option is (e).

Learn more:

1. The reason for the acidity of water brainly.com/question/1550328

2. Reason for the acidic and basic nature of amino acid. brainly.com/question/5050077

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Acids, bases, and salts

Keywords: Acid, bases, strong acids, pH , weak acids, electron-rich species, dissociation, moles of ions, HCl, H3O+, Cl-.

Darya [45]2 years ago
6 0

If you have an aqueous solution that contains 1.5 moles of HCl, the number of moles of ions in the solution is 3.0 moles.

<h2>Further Explanation </h2><h3>Strong acids  </h3>
  • Strong acids are types of acids that undergo complete dissociation to form ions when dissolved in water.
  • Examples of such acids are, HCl, H2SO4 and HNO3
  • Dissociation of HCl

HCl + H₂O ⇔ H₃O⁺ + OH⁻

<h3>Weak acids  </h3>
  • Weak acids are types of acids that undergo incomplete dissociation to form ions when dissolved in water.
  • Examples of such acids are acetic acids and formic acids.
  • Dissociation of  acetic acid

H₃COOH ⇔ CH₃COO⁻ + H⁺; CH₃COO⁻ is a conjugate base of acetic acid.

<h3>In this case;</h3>
  • HCl which is a strong acid that ionizes completely according to the equation;

HCl + H₂O ⇔ H₃O⁺ + OH⁻

  • From the equation, 1 mole of HCl produces 1 mole of H₃O⁺ ions and 1 mole of OH⁻ ions.

Therefore;

1.5 moles of HCl will produce;

= 1.5 moles of H₃O⁺ ions and 1.5 moles of OH⁻ ions.

This gives a total number ions of;

= 1.5 + 1.5

= 3 moles of ions

Keywords:  Strong acid, weak acid, ions, ionization

<h3>Learn more about: </h3>
  • Strong acid: brainly.com/question/3239966
  • Weak acid; brainly.com/question/3239966
  • Ionization of acids and bases: brainly.com/question/11844503

Level: High school

Subject: Chemistry

Topic: Salts, Acids and Bases

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5 0
3 years ago
200.0 mL of 3.85 M HCl is added to 100.0 mL of 4.6 M barium hydroxide. The reaction goes to completion. What is the concentratio
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Answer:

2.387 mol/L

Explanation:

The reaction that takes place is:

  • 2HCl + Ba(OH)₂ → BaCl₂ + 2H₂O

First we <u>calculate how many moles of each reagent were added</u>:

  • HCl ⇒ 200.0 mL * 3.85 M = 203.85 mmol HCl
  • Ba(OH)₂ ⇒ 100.0 mL * 4.6 M = 460 mmol Ba(OH)₂

460 mmol of Ba(OH)₂ would react completely with (2*460) 920 mmol of HCl. There are not as many mmoles of HCl so Ba(OH)₂ will remain in excess.

Now we <u>calculate how many moles of Ba(OH)₂ reacted</u>, by c<em>onverting the total number of HCl moles to Ba(OH)₂ moles</em>:

  • 203.85 mmol HCl * \frac{1mmolBa(OH)_{2}}{2mmolHCl}= 101.925 mmol Ba(OH)₂

This means the remaining Ba(OH)₂ is:

  • 460 mmol - 101.925 mmol = 358.075 mmoles Ba(OH)₂

There are two OH⁻ moles per Ba(OH)₂ mol:

  • OH⁻ moles = 2 * 358.075 = 716.15 mmol OH⁻

Finally we <u>divide the number of OH⁻ moles by the </u><u><em>total</em></u><u> volume</u> (100 mL + 200 mL):

  • 716.15 mmol OH⁻ / 300.0 mL = 2.387 M

So the answer is 2.387 mol/L

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Which of the following statements related to S N1 reactions is not true? - The heterolysis of a bond between atoms which do not
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Answer:

The charged carbon atom of a carbocation has a complete octet of valence shell electrons

Explanation:

A charged carbon atom of a carbocation has a valence shell that is not filled, <u>that's why it acts as an electrophile (or a Lewis base)</u>. This unfilled valence shell is also the reason of the nucleophilic attack that takes place during the second step of a SN1 reaction.

6 0
3 years ago
A 11.97g sample of NaBr contains 22.34 % Na by mass. Considering the law of constant composition (definite proportions), how man
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<h3>Answer:</h3>

2.125 g

<h3>Explanation:</h3>

We have;

  • Mass of NaBr sample is 11.97 g
  • % composition by mass of Na in the sample is 22.34%

We are required to determine the mass of 9.51 g of a NaBr sample.

  • Based on the law of of constant composition, a given sample of a compound will always contain the sample percentage composition of a given element.

In this case,

  • A sample of 11.97 g of NaBr contains 22.34% of Na by mass
  • Therefore;

A sample of 9.51 g of NaBr will also contain 22.345 of Na by mass

  • But;

% composition of an element by mass = (Mass of element ÷ mass of the compound) × 100

  • Therefore;

Mass of the element = (% composition of an element × mass of the compound) ÷ 100

Therefore;

Mass of sodium = (22.34% × 9.51 g) ÷ 100

                         = 2.125 g

Thus, the mass of sodium in 9.51 g of NaBr is 2.125 g

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2 years ago
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