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madam [21]
3 years ago
8

There are 650 sixth graders in the school and 338 of them are girls. What percent of the 6th grade students are girls?

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
4 0

Answer:

52% are girls

Step-by-step explanation:

We know that there are 650 sixth-graders and 338 of them are girls, we are then asked to find the percentage of how many are girls.

We have the fraction 338 over 650 but need to reduce it.

To solve this, we need to find the GCF of 650 and 338, which is 26, so divide both the numerator and denominator by 26.

\frac{338/26}{650/26}

\frac{13}{25}

Now divide the 13 and 25 :

13 / 25 = 0.52

0.52 * 100 = 52%

Therefore, 52% of the sixth-graders in the school are girls

JulsSmile [24]3 years ago
3 0

Answer: 52%

Step-by-step explanation:

338/650 and x/100 since we are trying to find a persentage, we have to make an proportion

338x100=33800 because we cross multiply

33800/650=52 because 33800 is now over 650

And 52 as a persentage is 52% which is how we get to our answer of 52%

I hope this helps

Hopefully it's brainliest

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Romashka [77]
C is correct.


Reasoning: If the top number (numerator) is smaller that the bottom number (denominator), it means it’s smaller than 1. If, on the other hand, the numerator is bigger than the denominator, it means it’s more than 1. If youre ever unsure, devide the numerator by the denominator. This will turn the number into a decimal, and be easier to see. 8/9 = 0.88 repeated, and 3/7 = 0.4285. Therefore 8/9 is larger than 3/7. This can also be written as 8/9 > 3/7.

Good luck!
7 0
3 years ago
Read 2 more answers
Which system is the only inconsistent system?
Sati [7]
The awnser is D. It's correct.

4 0
3 years ago
Mrs. Rogers' sister is two years older than Mrs. Rogers. Their combined ages add up to 88. How old is
saveliy_v [14]
42 because you take 46 and add 42 it will be 88 and the one sister is still 2 years older
7 0
3 years ago
Stephanie wants to buy her brother some UGA clothes before he starts school there. She has $55 to spend on him. The hats are $10
Anna35 [415]

Answer:

Part a: $10h + $15s ≤ $55

Part b: She can buy 3 shirts

Step-by-step explanation:

Part a: Write an equation to model the situation

Stephanie has $55 to spend.  Assume that hats are h, and shirts are s.

She can buy h hats for $10 each, represented as $10h

She can s shirts for $15 each, represented as $15s

She cannot spend more than $55

So that means $10h + $15s ≤ $55

It has to be less than or equal to because she can spend less money or $55 on her brother.

Part b: if she buys 1 hat, how many shirts can she buy?

Lets use our equation from part a

$10h + $15s ≤ $55

replace for for h because she bought 1 hat

$10 + $15s ≤ $55

Solve:

$10 + $15s ≤ $55

$15s ≤ $45

s ≤ 3

She can buy 3 shirts

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

4 0
3 years ago
In the figure below, \overline{AC} AC start overline, A, C, end overline and \overline{BE} BE start overline, B, E, end overline
mars1129 [50]

Answer:

arc\ DBE=206^o

Step-by-step explanation:

The picture of the question in the attached figure

<u><em>The question is</em></u>

Find the measure of arc DBE          

step 1

Find the value of k

we know that

m\angle EPC=90^o ----> by quarter of circle

m\angle EPC=(33k-9)^o

so

(33k-9)^o=90^o

solve for k

33k=90+9\\33k=99\\k=3

step 2

Find the measure of angle DPC

we know that

m\angle DPC=(20k+4)^o

substitute the value of k

m\angle DPC=(20(3)+4)=64^o

step 3

Find the measure of angle BPD

we know that

m\angle BPD+m\angle DPC=90^o ---> by complementary angles

substitute the given value

m\angle BPD+64^o=90^o

m\angle BPD=90^o-64^o=26^o

step 4

Find the measure of arc DBE

we know that

arc\ DBE=arc\ DB+arc\ BAE

arc\ DB=m\angle BPD=26^o ----> by central angle

arc\ BAE=180^o ---> because a diameter divide the circle into two equal parts (BE is a diameter)

substitute

arc\ DBE=26^o+180^o=206^o

8 0
3 years ago
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