Question

Assume that the Poisson distribution applies and that the mean number of hurricanes in a certain area is 5.1 per year.

Answer 1

Answer:

a) 0.172 probability that, in a year, there will be 4 hurricanes.

b) The expected number of years with 4 hurricanes is 7.7.

c) 7 years is close to the expected value of 7.7, which means that the Poisson distribution works well here.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

The mean number of hurricanes in a certain area is 5.1 per year.

This means that $\mu = 5.1$

a. Find the probability that, in a year, there will be 4 hurricanes.

This is P(X = 4).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 4) = \frac{e^{-5.1}*(5.1)^{4}}{(4)!} = 0.172$

0.172 probability that, in a year, there will be 4 hurricanes.

b. In a 45-year period, how many years are expected to have 4 hurricanes?

Each year, 0.172 probability of 4 hurricanes. So for 45 years, the mean is 45*0.172 = 7.7.

The expected number of years with 4 hurricanes is 7.7.

c. How does the result from part (b) compare to a recent period of 45 years in which 7 years had 4 hurricanes? Does the Poisson distribution work well here?

7 years is close to the expected value of 7.7, which means that the Poisson distribution works well here.