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3 years ago

HW HELP ASAP PLZZZZZZ

Mathematics

1 answer:

astraxan [27]3 years ago

5 0

Graph 2 should be right because it moves up 1 because of the +1 that is in the parentheses.

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Which of the following equations has the same solutions as the equation 3x + 2y = -12? Check all that apply.

Mariulka [41]

Answer:

$B.\ -3x - 2y = 12$

$C.\ 15x + 10y = -60$

$E.\ 6x + 4y = -24$

$F.\ 1.5x + y =-6$

Step-by-step explanation:

Given

$3x + 2y = -12$

Required

Determine equations with same solution as $3x + 2y = -12$

For a solution to have the same solution as $3x + 2y = -12$ , the equation must be expressed as $3x + 2y = -12$

$A.\ 3x - 2y = 12$

This can not be expressed as $3x + 2y = -12$

$B.\ -3x - 2y = 12$

Multiply through by -1

$-1(-3x - 2y) = 12 * -1$

$3x + 2y = -12$

This has the same solution as the given equation

$C.\ 15x + 10y = -60$

Divide through by 5

$\frac{15x}{5} + \frac{10y}{5} = \frac{-60}{5}$

$3x + 2y = -12$

This has the same solution as the given equation

$D.\ 6x + 2y = -12$

Divide through by 2

$\frac{6x}{2} + \frac{2y}{2} = \frac{-12}{2}$

$3x + y = -6$

This can not be expressed as $3x + 2y = -12$

$E.\ 6x + 4y = -24$

Divide through by 2

$\frac{6x}{2} + \frac{4y}{2} = \frac{-24}{2}$

$3x + 2y = -12$

This has the same solution as the given equation

$F.\ 1.5x + y =-6$

Multiply through by 2

$2*1.5x + 2*y =-6*2$

$3x + 2y =-12$

This has the same solution as the given equation

$G.\ x + \frac{2}{3}y = -12$

Multiply through by 3

$3 * x + 3*\frac{2}{3}y = -12*3$

$3x + 2y = -36$

This can not be expressed as $3x + 2y = -12$

The equations with the same solution as $3x + 2y = -12$ are the ones that we were able to expressed as $3x + 2y = -12$ .

And the equations are:

$B.\ -3x - 2y = 12$

$C.\ 15x + 10y = -60$

$E.\ 6x + 4y = -24$

$F.\ 1.5x + y =-6$

7 0

3 years ago

Please help for a cookie

olasank [31]

Answer:

Step-by-step explanation:

4 0

3 years ago

(A+B)^2<br> Giúp mình với ạ

bija089 [108]

Answer:

= a^2 + 2.a.b + b^2

4 0

3 years ago

Each sequence below gives an explicit formula. Write the first five terms of each sequence. Then, write a recursive

Bas_tet [7]

Answer:

The first five values are 12, 14, 16, 18 and 20

The recursive formula is as follow

$\left \{ {{a_{1} =12} \atop {a_{n} =a_{n-1} } + 2} \right.$

Step-by-step explanation:

Since we need to find the first 5 values we start with n = 1 to n = 5. Note that we don't start from n = 0 as the question states that n ≥ 1.

For the first 5 values we just replace the value of n with 1, 2, 3, 4 and 5 and calculate the answer

$a_{1} = 2(1) + 10 = 12\\ a_{2} = 2(2) + 10 = 14\\ a_{3} = 2(3) + 10 = 16\\ a_{4} = 2(4) + 10 = 18\\ a_{5} = 2(5) + 10 = 20$

The first five values are 12, 14, 16, 18 and 20

A recursive formula is one that

a) Mentions the initial term

b) provides a formula connecting the previous term to the existing term.

Since we know the first term is 12, i.e $a_{1} = 12$ and we know that the difference between consecutive terms is 2 we can conclude that the recursive formula is made up of the following two formulas

$a_{1} = 12$

$a_{n} = a_{n-1} + 2$

The over all formula is as follow

$\left \{ {{a_{1} =12} \atop {a_{n} =a_{n-1} } + 2} \right.$

8 0

3 years ago

What is a linear equation that contains these points?

shepuryov [24]

Answer:

Step-by-step explanation:

If you plug in the numbers into that equation you get

1 = -2(2) + 5

1 = -4 + 5

1 = 1

You can also do this again with x = 5 y = -5

-5 = -2(5) + 5

-5 = -10 + 5

-5 = -5

7 0

3 years ago