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hram777 [196]
3 years ago
15

Tickets to the concert were 2.50 for adults and $1 for students. $1200 was collected and 750 tickets were sold. Write a system o

f linear equations that can be used to find how many adults and how many students attended. How many students attended?
Mathematics
2 answers:
serious [3.7K]3 years ago
4 0

Answer:

300 adults and 450 students

Step-by-step explanation:

We can set-up a system of equations to find the number of adults. We know students and adults attended. We will let s be the number of students and a be the number of adults. Since 750 people attended, then s+a=750.

We also know they made $1200 and adult tickets cost $2.50 and student tickets cost $1. We can write 1s+2.5a=1200.

We will solve by substituting one equation into the other. We start by solving the first equation for c. s+a=750 becomes s=750-a.

Now we substitute s=750-a into 1s+2.5a=1200. Simplify and isolate the variable a.

  • 1(750-a)+2.5a=1200
  • 750-a+2.5a=1200
  • 750+1.5a=1200
  • 750-750+1.5a=1200-750
  • 1.5a=450
  • a=300

This means that 300 adults attended and 450 students attended since 300+450=750.


yKpoI14uk [10]3 years ago
3 0

Answer:

Step-by-step explanation:

0 all triangles must add up to 180 degrees.

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The Edward James Toy Company uses a Kanban system to make plastic wheels that are a component of several toys. The waiting time
pickupchik [31]

Answer:

N_c \approx 5.0

Step-by-step explanation:

From the question we are told that:

Waiting time for a container of the wheels during production T_w=0.25day

Average processing time is T_a=0.15 day per container

Wheel per container N_w=200

Total wheel per day D=2000

Policy variable of X=5%  

Generally the equation for Total number of container N_c is mathematically given by

N_c=DT(\frac{1+X}{N_w} )

Where

Total time T=T_w+T_a

T=0.15+0.25

Therefore

N_c=DT(\frac{1+X}{N_w} )

N_c=2000*0.40(\frac{1+0.5}{200} )

N_c=(\frac{840}{200} )

N_c=4.2

N_c \approx 5.0

Therefore the number of Kanban containers needed for the wheels is

N_c \approx 5.0

3 0
2 years ago
1.
olchik [2.2K]
To solve this we are going to use the future value of annuity ordinary formula: FV=P[ \frac{(1+ \frac{r}{n} )^{kt} -1}{ \frac{r}{n} } ]
where
FV is the future value
P is the periodic payment
r is the interest rate in decimal form
n is the number of times the interest is compounded per year
k is the number of payments per year
t is the number of years

We know for our problem that P=6200 and t=5. To convert the interest rate to decimal form, we are going to divide the rate by 100%:
r= \frac{6}{100} =0.06
Since the deposit is made semiannually, it is made 2 times per year, so k=2.
Since the type of the annuity is ordinary, payments are made at the end of each period, and we know that we have 2 periods, so n=2.
Lets replace the values in our formula:

FV=P[ \frac{(1+ \frac{r}{n} )^{kt} -1}{ \frac{r}{n} } ]
FV=6200[ \frac{(1+ \frac{0.06}{2} )^{(2)(5)} -1}{ \frac{0.06}{2} } ]
FV=71076.06

We can conclude that the correct answer is <span>$71,076.06</span>
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Answer: I have no clue but I’ll look into it

Step-by-step explanation:

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Step-by-step explanation:

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