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elixir [45]
3 years ago
5

A ramp has a horizontal distance of 10 feet and a vertical rise of 3 feet. Find the length of the ramp. Round to the nearest ten

th.
Mathematics
1 answer:
Alona [7]3 years ago
5 0

Answer:Gygggyj

Step-by-step explanation:

You might be interested in
Changing the mean and standard deviation of a Normal distribution by a moderate amount can greatly change the percent of observa
sweet-ann [11.9K]

Answer:

a) P(X>750)=P(\frac{X-\mu}{\sigma}>\frac{750-\mu}{\sigma})=P(Z1.798)

P(Z>1.798)=1-P(z

f. 3.59 %

b) P(X>750)=P(\frac{X-\mu}{\sigma}>\frac{750-\mu}{\sigma})=P(Z2.21)

P(Z>2.21)=1-P(Z

d. 1.36 %

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the scores of men of a population, and for this case we know the distribution for X is given by:

X \sim N(527,124)  

Where \mu=65.5 and \sigma=2.6

We are interested on this probability

P(X>750)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>750)=P(\frac{X-\mu}{\sigma}>\frac{750-\mu}{\sigma})=P(Z1.798)

And we can find this probability using the complement rule and with the normal standard distribution table or excel:

P(Z>1.798)=1-P(Z

So then the correct answer for this case would be:

f. 3.59 %

Part b

Let X the random variable that represent the scores of women's of a population, and for this case we know the distribution for X is given by:

X \sim N(496,115)  

Where \mu=496 and \sigma=115

We are interested on this probability

P(X>750)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>750)=P(\frac{X-\mu}{\sigma}>\frac{750-\mu}{\sigma})=P(Z2.21)

And we can find this probability using the complement rule and with the normal standard distribution table or excel:

P(Z>2.21)=1-P(Z

So then the correct answer for this case would be:

d. 1.36 %

7 0
3 years ago
I need help solving this problem. Thanks
Kamila [148]

9514 1404 393

Answer:

  y = -4/7x +58/7

Step-by-step explanation:

The slope of the given line segment is ...

  m = (y2 -y1)/(x2 -x1)

  m = (17 -3)/(1 -(-7)) = 14/8 = 7/4

Then the slope of the perpendicular line is ...

  -1/m = -4/7 . . . . . slope of the perpendicular bisector.

__

The midpoint of the given line segment is ...

  M = 1/2(x1 +x2, y1 +y2)

  M = (1/2)(-7 +1, 3 +17) = 1/2(-6, 20) = (-3, 10)

__

The y-intercept of the bisector can be found from ...

  b = y -mx

  b = 10 -(-4/7)(-3) = 10 -12/7 = 58/7

Then the slope-intercept form equation for the perpendicular bisector is ...

  y = mx +b

  y = -4/7x +58/7

6 0
3 years ago
Canadians who visit the United States often buy liquor and cigarettes, which are much cheaper in the United States. However, the
fenix001 [56]

Answer:

(a): Marginal pmf of x

P(0) = 0.72

P(1) = 0.28

(b): Marginal pmf of y

P(0) = 0.81

P(1) = 0.19

(c): Mean and Variance of x

E(x) = 0.28

Var(x) = 0.2016

(d): Mean and Variance of y

E(y) = 0.19

Var(y) = 0.1539

(e): The covariance and the coefficient of correlation

Cov(x,y) = 0.0468

r \approx 0.2657

Step-by-step explanation:

Given

<em>x = bottles</em>

<em>y = carton</em>

<em>See attachment for complete question</em>

<em />

Solving (a): Marginal pmf of x

This is calculated as:

P(x) = \sum\limits^{}_y\ P(x,y)

So:

P(0) = P(0,0) + P(0,1)

P(0) = 0.63 + 0.09

P(0) = 0.72

P(1) = P(1,0) + P(1,1)

P(1) = 0.18 + 0.10

P(1) = 0.28

Solving (b): Marginal pmf of y

This is calculated as:

P(y) = \sum\limits^{}_x\ P(x,y)

So:

P(0) = P(0,0) + P(1,0)

P(0) = 0.63 + 0.18

P(0) = 0.81

P(1) = P(0,1) + P(1,1)

P(1) = 0.09 + 0.10

P(1) = 0.19

Solving (c): Mean and Variance of x

Mean is calculated as:

E(x) = \sum( x * P(x))

So, we have:

E(x) = 0 * P(0)  + 1 * P(1)

E(x) = 0 * 0.72  + 1 * 0.28

E(x) = 0   + 0.28

E(x) = 0.28

Variance is calculated as:

Var(x) = E(x^2) - (E(x))^2

Calculate E(x^2)

E(x^2) = \sum( x^2 * P(x))

E(x^2) = 0^2 * 0.72 + 1^2 * 0.28

E(x^2) = 0 + 0.28

E(x^2) = 0.28

So:

Var(x) = E(x^2) - (E(x))^2

Var(x) = 0.28 - 0.28^2

Var(x) = 0.28 - 0.0784

Var(x) = 0.2016

Solving (d): Mean and Variance of y

Mean is calculated as:

E(y) = \sum(y * P(y))

So, we have:

E(y) = 0 * P(0)  + 1 * P(1)

E(y) = 0 * 0.81  + 1 * 0.19

E(y) = 0+0.19

E(y) = 0.19

Variance is calculated as:

Var(y) = E(y^2) - (E(y))^2

Calculate E(y^2)

E(y^2) = \sum(y^2 * P(y))

E(y^2) = 0^2 * 0.81 + 1^2 * 0.19

E(y^2) = 0 + 0.19

E(y^2) = 0.19

So:

Var(y) = E(y^2) - (E(y))^2

Var(y) = 0.19 - 0.19^2

Var(y) = 0.19 - 0.0361

Var(y) = 0.1539

Solving (e): The covariance and the coefficient of correlation

Covariance is calculated as:

COV(x,y) = E(xy) - E(x) * E(y)

Calculate E(xy)

E(xy) = \sum (xy * P(xy))

This gives:

E(xy) = x_0y_0 * P(0,0) + x_1y_0 * P(1,0) +x_0y_1 * P(0,1) + x_1y_1 * P(1,1)

E(xy) = 0*0 * 0.63 + 1*0 * 0.18 +0*1 * 0.09 + 1*1 * 0.1

E(xy) = 0+0+0 + 0.1

E(xy) = 0.1

So:

COV(x,y) = E(xy) - E(x) * E(y)

Cov(x,y) = 0.1 - 0.28 * 0.19

Cov(x,y) = 0.1 - 0.0532

Cov(x,y) = 0.0468

The coefficient of correlation is then calculated as:

r = \frac{Cov(x,y)}{\sqrt{Var(x) * Var(y)}}

r = \frac{0.0468}{\sqrt{0.2016 * 0.1539}}

r = \frac{0.0468}{\sqrt{0.03102624}}

r = \frac{0.0468}{0.17614266944}

r = 0.26569371378

r \approx 0.2657 --- approximated

8 0
2 years ago
Help pls!! I need help!!
AlladinOne [14]

Answer:

what u need help wt?

Step-by-step explanation:

6 0
3 years ago
1. Choose the appropriate symbol to make the following statment true. 0.586_0.568
exis [7]

Answer:

>

Step-by-step explanation:

8 0
3 years ago
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