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maria [59]
3 years ago
9

If x = 3 and y = -1, then 3x2 + 2xy - 5 = ? A: 18 B: 24 C: 12 D: 16

Mathematics
2 answers:
iris [78.8K]3 years ago
8 0
x = 3 , \ y = -1 \\ \\ 3x^2 + 2xy - 5 = 3\cdot 3^2 + 2\cdot 3\cdot (-1)-5=\\ \\=3\cdot 9 -6-5=27-11=16 \\ \\ Answer : \ D: \ \ 16


Alona [7]3 years ago
4 0
3\cdot3^2+2\cdot3\cdot(-1)-5=27-6-5=16
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<h3><u>Solution:</u></h3>

Given that square has side length (x+5) units

To find: area of square

<em><u>The area of square is given as:</u></em>

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Where "a" is the length of side

From question, length of each side "a" = x + 5 units

Substituting the value in above formula,

\text {Area of square }=(x+5)^{2}

{\text {Expanding }(x+5)^{2} \text { using the algebraic identity: }} \\\\ {(a+b)^{2}=a^{2}+2 a b+b^{2}}\end{array}

\begin{array}{l}{\text {Area of square }=x^{2}+2(x)(5)+5^{2}} \\\\ {\text {Area of square }=x^{2}+10 x+25}\end{array}

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