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3 years ago

Happy new year ✨ ☺ ✨ ☺

Mathematics

2 answers:

solong [7]3 years ago

4 0

Answer:

happy new year

Step-by-step explanation:

Dmitry [639]3 years ago

4 0

Answer:

Negative association

Step-by-step explanation:

As you can see on table y the numbers are going down.

And I am not sure if you understand me but I can't explain very well sorry.

Hope this helped and Goodluck!!!

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Tim predicts he will get 98 points on the next exam. If Tim actually earned 62 points, what was Tim's percent error? Round your

Mariana [72]

98 - 62 = 36

36/98 x 100 = 36.7%

answer:

Tim was 36.7% error

5 0

3 years ago

Read 2 more answers

6 calculators cost $160 what is the rate and the unit rate

BigorU [14]

Answer:

$\dfrac{\$160}{6~calculators}$

$\dfrac{\$26.67}{calculator}$

Step-by-step explanation:

The rate for the 6 calculators is

$\dfrac{\$160}{6~calculators}$

To find the unit rate, divide 160 by 6.

The unit rate is

$\dfrac{\$26.67}{calculator}$

6 0

3 years ago

Solve the following equation.<br>6cos²x - 7cosx + 1 = 0, for <br>0° ≤ x ≤ 360°

larisa [96]

Answer:

For 0° ≤ x ≤ 360° we have:

x=0, 360, arccos(1/6), -arccos(1/6)

Step-by-step explanation:

Replace cos(x) by y

6y²-7y+1=0

6y²-6y-y+1=0

6y(y-1) -(y-1)=0

(y-1)(6y-1)=0

Roots:

y=1, cos(x)=1, x=0 and 360

y=1/6, cos(x)=1/6, x=arccos(1/6) and x=-arccos(1/6)

7 0

4 years ago

Read 2 more answers

9. 4⁄15 of the 315 members of a book club are male. How many female members are there in the club?

oee [108]

You take 4/15 and make the denominator 315

4/15 = ?/315
15 x 21 = 315
4 x 21 = 84
4/15 = 84/315

so 84 of 315 members are male

315 - 84
= 231

231 are female

3 0

4 years ago

A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What

Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

$P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}$

a) What is the probability that none of the questions are essay?

$P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174$

b) What is the probability that at least one is essay?

$P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232$

c) What is the probability that two or more are essay?

$P(X\geq2)=1-(P(0)+P(1))=1-(0.3174+0.4232)=1-0.7406=0.2594$

8 0

4 years ago

Happy new year ✨ ☺ ✨ ☺ ​

Happy new year ✨ ☺ ✨ ☺