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2 years ago

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Mercury metal is poured into a graduated cylinder that holds exactly 22 the mercury used to fill the cylinder weighs 308 from th

is information calculate the destiny of Mercury

1 answer:

gogolik [260]2 years ago

7 0

Answer:

Answer: Mercury metal is poured into a graduated cylinder that holds exactly 22.5 mL. The mercury used to fill the cylinder weighs 306.0 g

Step-by-step explanation:

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Find the commission.<br> Earning Commission | sales = $530 | commision rate = 3% | commision = ?

sergij07 [2.7K]

Answer:

$15. 90

Step-by-step explanation:

3% of 530= 15.9

4 0

2 years ago

Read 2 more answers

Finding Derivatives Implicity In Exercise,Find dy/dx implicity.<br> x2e - x + 2y2 - xy = 0

Klio2033 [76]

Answer:

the question is incomplete, the complete question is

"Finding Derivatives Implicity In Exercise,Find dy/dx implicity . $x^{2}e^{-x}+2y^{2}-xy$ "

Answer : $\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}$

Step-by-step explanation:

From the expression $x^{2}e^{-x}+2y^{2}-xy$ " y is define as an implicit function of x, hence we differentiate each term of the equation with respect to x.

we arrive at

$\frac{d}{dx}(x^{2}e^{-x )+\frac{d}{dx} (2y^{2})-\frac{d}{dx}xy=0\\$

for the expression $\frac{d}{dx}(x^{2}e^{-x})$ we differentiate using the product rule, also since y^2 is a function of y which itself is a function of x, we have

$(2xe^{-x}-x^{2}e^{-x})+4y\frac{dy}{dx}-x\frac{dy}{dx} -y=0\\\\(2-x)xe^{-x}+(4y-x)\frac{dy}{dx}-y=0 \\$ .

if we make dy/dx subject of formula we arrive at

$(4y-x)\frac{dy}{dx}=y-(2-x)xe^{-x}\\\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}$

5 0

3 years ago

8th grade math help please zoom in on the question for a better look (will give brainliest and thanks if it's right)

eduard

The two pairs are Pythagorean triples because if you plug the two legs of a right triangle into the Pythagorean theorem(A^2+B^2=C^2), then you will find the measurement for the third side(hypotenuse). i.e. 15^2+12^2=9^2(it's the Pythagorean triple 3,4,5 multiplied by 3). This works with any triple, as long as your using the legs of the triangle and as long as the triangle is a right triangle.

5 0

2 years ago

The initial cost of an office fax machine is $100. After 1 year, its value becomes $80. Which is the correct linear depreciation

Elis [28]

Answer:

$y=100-20x$

Step-by-step explanation:

Let the x-axis be the time (in years) and the y-axis the value of the fax machine (in dollars).

We know that the initial value of the fax machine is $100; in other words, when the time is zero years, the value is $100, or as an ordered pair (0, 100). We also know that after 1 year the value decreases to $80, so (1, 80).

Now we can find the slope of the line passing through those two points using the slope formula

$m=\frac{y_2-y_1}{x_2-x_1}$

where

$m$ is the slope

$(x_1,y_1)$ are the coordinates of the first point

$(x_2,y_2)$ are the coordinates of the second point

Replacing values:

$m=\frac{80-100}{1-0}$

$m=-20$

Now, to complete our model we are using the point slope formula

$y-y_1=m(x-x_1)$

where

$m$ is the slope

$(x_1,y_1)$ are the coordinates of the first point

Replacing values:

$y-100=-20(x-0)$

$y-100=-20x$

$y=-20x+100$

$y=100-20x$

We can conclude that the correct linear depreciation model is $y=100-20x$

7 0

2 years ago

Least to greatest. 26.2, 262%, 2 3/5 (two and three fifths)

9966 [12]

Answer:

Step-by-step explanation:

BACD

3 0

2 years ago