Answer: There is 40% of team's win that Ryan score a goal.
Step-by-step explanation:
Since we have given that
Team Won Team lost
Ryan scored 6 4
Did not score 9 11
(by Ryan)
-------------------------------------------------------------------------
Total 15 15
Percentage of team's win that Ryan score a goal is given by
Hence, there is 40% of team's win that Ryan score a goal.
Let's solve your inequality step-by-step.
<span><span><span>
a − 8 </span>+ 15 </span>> <span>23
</span></span>Step 1: Simplify both sides of the inequality.
<span><span><span><span><span>
−1/</span>8</span>a </span>+ 15 </span>> 23
</span>
Step 2: Subtract 15 from both sides.
<span><span><span><span><span><span>
−1/</span>8</span>a </span>+ 15 </span>− 15 </span>> <span>23 − 15
</span></span><span><span><span><span>
−1/</span>8</span>a </span>> 8
</span>
Step 3: Multiply both sides by 8/(-1).
<span><span><span>
(<span>8/<span>−1</span></span>) </span>* <span>(<span><span><span>−1/</span>8</span>a</span>) </span></span>> <span><span>(<span>8/<span>−1</span></span>) </span>* <span>(8)
</span></span></span><span>
a < <span>−<span>64
Therefore, the answer is a < -64! I hope this helped! :)</span></span></span>
Completed question:
In the game of tic-tac-toe, if all moves are performed randomly the probability that the game will end in a draw is 0.127. Suppose six random games of tic-tac-toe are played. What is the probability that at least one of them will end in a draw?
Answer:
0.557
Step-by-step explanation:
For each game, the probability of not end in a draw is 1 - 0.127 = 0.873. Thus, because each game is independent of each other, the probability of all of them not end in a draw is the multiplication of the probability of each one:
0.873x0.873x0.873x...x0.873 = 0.873⁶ = 0.443
Thus, the probability that at least one of them end in a draw is the total probability (1) less the probability that none of them en in a draw:
1 - 0.443
0.557
Answer:
A)
Step-by-step explanation:
