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lesantik [10]
3 years ago
10

Determine if the lines are parallel, perpendicular, or neither 4x+5y=10 and 5x -4y= 28

Mathematics
1 answer:
Viktor [21]3 years ago
6 0
To do this, we will need to compare the slopes and the y int. So we will put each equation in y = mx + b form, where m will be the slope and b will be the y int..

4x + 5y = 10
5y = -4x + 10
y = -4/5x + 2.....the slope here is -4/5...the y int is 2

5x - 4y = 28
-4y = -5x + 28
y = 5/4x - 7...the slope here is 5/4...and the y int is -7

for the lines to be parallel, they would need the same slope and different y intercepts. So, as u can see, they are not parallel because they do not have the same slope.

for the lines to be perpendicular, the lines would have to have negative reciprocal slopes. They do....u have perpendicular lines. To find the negative reciprocal of a number, u flip the number and change the sign. One line had a slope of -4/5....the negative reciprocal is : flip the number making it -5/4....change the sign, making it 5/4...which is the slope of the other line...so these slopes are negative reciprocals.

so u have perpendicular lines
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3 years ago
Which statement is true about the product square root of 2(3square root of 2 + square root of 14)?
sukhopar [10]

Answer:

\sqrt{2} (3\sqrt{2} +\sqrt{14})=6+2\sqrt{7}

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3 years ago
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