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3 years ago

7

In a fundraiser for thanksgiving a student sells pizza. If a box of pizza cost $14.50 and he sold it for $20.50. What is the mar

kup rate on each box? Round to the nearest percent

1 answer:

oee [108]3 years ago

8 0

Answer:

The markup rate on each box=41%

Step-by-step explanation:

The markup rate is the additional price that a good is sold at expressed as a percentage. This can be expressed as;

R={(S-C)/C}×100

where;

R=markup rate

S=selling price

C=cost

In our case;

R=unknown

S=$20.50

C=$14.50

replacing;

R={(20.5-14.5)/14.5}×100

R=(6/14.5)×100

R=41.38% rounded off=41%

The markup rate on each box=41%

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(2x + y = -2<br> (5x + 3y = -8<br> Solve by substitution

aliya0001 [1]

(2, -6)

Step-by-step explanation:

y = -2 - 2x

5x + 3 (-2-2x) = - 8

5x - 6 - 6x = - 8

-x - 6 = 8

- 6 + 8 = x

2 = x

x = 2

y = -2 -2x

y = -2 -2(2)

y = -2 -4

y = -6

(x, y) = (2, -6)

3 0

2 years ago

Read 2 more answers

PLEASE HELP! ILL MARK !!

mylen [45]

Answer:

c) tan

Step-by-step explanation:

tan = Opposite side / close side

When close side = v and Opposite side = 2,8m

8 0

3 years ago

3. A team of eye surgeons has developed a new technique for a risky eye operation to restore the

Zigmanuir [339]

Answer:

Yes the new method if sample size was less than 20 than that of old method or identical sample numbers of old and new the differences still prove the new operation is better. As 88 patients minus 1% still shows us 76.7475 significance of old method being low point 67.5 = 30% of 225 and proved a 65.25 low point and 69.75 high point which is also a 20% jump to new methods low point significance.

You cna show this as workings to prove or follow any of the below statements.

Where new method of 88 patients -0.01 significance rate stands at 76.7475. This figure has reduced by 11.2525 from 88 patients to 76.7 we compare this to the old method if reversing significance we find = 62.5 and it's 30% standing value of 67.5 as +1% increase shows us 31% = 69.7 ( 0.31 x 225 = 69.74)

Step-by-step explanation:

88/225 = 0.39111111111 = 39.11%%

P value 01 = 1% = 225.225 or 5% range of alternative hypotheses.

To graph the P value we take the distance between the sample mean and the null hypothesis value (225 + 1% of sample - x nhv) = y ). We can graph the probability of obtaining a sample mean (225 +/- ( x +1% of sample) where nhv has a decimal if needed to utilize the 1% added). we would replace nvp in this example with Ha or H1 which means the alternative hypotheses as the data shows less than or equal to.

We can then show 225.225 - Ha or H1 then graph the probability of obtaining a sample mean that is at least extreme in both tails Ha or H1

However it would be the other way round where you take the first set of data and use the sample as the 30% significance of that sample indicates it may be a larger sample or a higher significance. Therefore this would be used in the graphing - 1%

We prove that 30-1 =29 where 29% of 225 = 225 x 0.29 = 65.25

this way we have proved that the new set of data being equal to 88 patients regaining their eyesight is <23 and can be written like this 65.25< x <88

This means that sample mean has taken the 1% to show on the graph we can show 225> 33.11 +1 .

We can prove that both indifference of significance would reduce when 1% is added and close based on being a higher percentage to begin with.

34.11 = 0.3411 x 225 = 76.7475 for second surgeon = 33.11% +1

Where as shown

30 = 0.3 x 225 = 67.5

76.5475 - 67.5 = 9.04 difference when comparing old method = +1%

where new method stands at 76.7475 has reduced by 11.2525 from 88 patients and where old method if reversing = 62.5 and has reduced from 67.5 as +1% and 31% = 69.7 ( 0.31 x 225 = 69.74)

You would therefore graph each higher methods first if comparing both by 0.01 or show 88 on graph and 76.7475 = +1%

NB/ if sample size was 20 more in the old data then 225+20 = 245 x 0.29 = 71.05 and would still be lower than new data. = 2.0 increase level of significance and not relevant unless you are looking for the decrease which means new is greater than 20% success than that of old method findings where 30% = 67.5.

5 0

3 years ago

Find the discriminant of the following quadratic equation<br> x^-5x+3=0

nika2105 [10]

The discriminant of the given quadratic equation as in the task content can be evaluated by means of the formula; D = b²-4ac and it's value is; 13.

<h3>What is the discriminant of the quadratic equation as given in the task content?</h3>

According to the task content, it follows that the quadratic equation whose discriminant is to be determined is; x²-5x+3=0.

By comparison with the standard form equation of a quadratic graph which goes thus; ax²+bx +c = 0, in which case, the determinant is given by the expression; b² - 4ac.

We can consequently evaluate the determinant of the quadratic equation in discuss as follows;

Determinant = b² -4ac = (-5)² - (4×1×3) = 25 - 12

Hence, the determinant in this case is; 13.

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1 year ago

If Florist B increases the cost per rose to $5.20,for what number of roses is it less expensive to order from Florist A? From Fl

Alenkinab [10]

Answer:

For<em> </em>38 roses at <em>$5.15</em> per rose, Florist A is Less Expensive then Florist B

For<em> </em>34 roses at <em>$5.20</em> per rose, Florist A is Less Expensive then Florist B

Step-by-step explanation:

The Full Question Reads:

<u><em>Derek wants to order some roses online. Florist A charges $4.75 per blue rose plus $40 delivery charge. Florist B charges $5.15 per red rose plus $25 delivery charge. If Florist B increases the cost per rose to $5.20, for what number of roses is it less expensive to order from Florist A? From Florist B?</em></u>

To begin we need to understand our given information and what we are actually looking for.

<u>Given Information</u>

Florist A:

charges $4.75 per blue rose

charges $40 per delivery

Florist B:

charges $5.15 per red rose

charges $25 per delivery

Note: in this problem we ignore the colour of the rose (red or blue) as it does not affect our solution or contributes to it. Therefore we shall call our first variable representing the number of roses as $x$ .

The next step is to construct a system of equations representing our problem and our given information. Here we are looking at linear relationships so a linear function of the form:

$y=ax+b$ Eqn(1).

<em>will suffice where</em>

$y$ : represents the total cost from the Florists (i.e. number of roses and delivery charges). Dependent Variable

$x$ : represents the number of roses purchased from the Florists. Independent Variable

$a$ : is our relationship factor between $y$ and $x$

$b$ : is our constant which in this problem is the <em>delivery charge</em> value for each florist.

Since we have two Florists, we will construct two equations, one for each florist, by employing Eqn(1). and our given information as follow:

Florist A: $y=4.75x+40$ Eqn(2).

Florist B: $y=5.15x+25$ Eqn(3).

By employing both equations above and writing them as an inequality <em>since we are looking for which value of </em> $x$ <em> (i.e. number of roses) will the less expensive Florist be and then solving for </em> $x$ <em> we have: </em>

<em> $4.75x+40$ </em>

<em> $4.75x-5.15x$ Gathering all similar terms together</em>

<em> $-0.4x$ Simplifying</em>

<em> $x>\frac{-15}{-0.4}\\$ Solving for x </em>

<em> $x>37.5$ </em>

<em>(note how < changes to > since any multiplication/devision process of negative sign in an Inequality will change the order of < to > and vice versa). </em>

Since a rose has to be sold as a whole and not half we will say that <em> $x>38$ </em> So we can then plug in the value of $x$ in Eqn(2) and Eqn(3) and find the cost of buying more than 38 roses from each:

Eqn(2): Florist A: $y(x>38)=4.75*38+40=220.5$

Eqn(3): Florist B: $y(x>38)=5.15*38+25=220.7$

Which tells us that Florist A is less expensive than Florist B by $0.20 for a purchase of more than 38 roses.

Next the question tells us that Florist B increases the cost from $5.15 to $5.20 per rose, which in Eqn(3) denotes our $a$ value and thus Eqn(3). now becomes:

Florist B: $y=5.20x+25$ Eqn(3).

Applying the same method like before and solving for the value of $x$ <em> we have: </em>

<em> $4.75x+40$ </em>

<em> $4.75x-5.20x$ Gathering all similar terms together</em>

<em> $-0.45x$ Simplifying</em>

<em> $x>\frac{-15}{-0.45}\\$ Solving for x </em>

<em> $x>33.3$ </em>

Similarly as a rose has to be sold as a whole and not half we will say that <em> $x>34$ </em> So we can then plug in the value of $x$ in Eqn(2) and Eqn(3) and find the cost of buying more than 34 roses from each:

Eqn(2): Florist A: $y(x>34)=4.75*34+40=201.5$

Eqn(3): Florist B: $y(x>34)=5.15*34+25=201.8$

Which tells us that Florist A is again less expensive than Florist B by $0.30 for a purchase of more than 34 roses. It was also shown that as the cost of the rose increased by $0.05 the number of roses for purchase decreased.

4 0

3 years ago