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3 years ago

-3x - 5 = 16

Mathematics

1 answer:

garik1379 [7]3 years ago

4 0

Add five to both sides
-3x = 21
Divide by -3 on both sides
x = -7

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Can somebody help with this please dont put fake answers i really need to pass this test

tekilochka [14]

Step-by-step explanation:

by using Pythagoras theorem,

h^2= p^2+b^2

or, b^2=h^2- p^2

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3 years ago

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A computer that originally cost $850 is on sale for 15% Off. What is sale price of the computer? Help Please <3 Thanks!

zaharov [31]

Percent means per 100
think cent as in 100 pennies in a dollar

To convert from percent to decimal, we divide by 100 or move the decimal over 2 spots, so,
15% = 15/100 = 0.15

Now multiply 0.15 by 850 to find the discount saved
0.15*850 = 127.50
So you'll save $127.50

The final price is therefore: 850-127.50 = 722.50

A shortcut is to multiply 850 by 0.85
850*0.85 = 722.50
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The 0.85 comes from the fact that if you get 15% off, then you pay 85% of the original price

Answer: $722.50

6 0

3 years ago

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What is the area of ABC?

Salsk061 [2.6K]

Answer:

Area of triangle ABC = 10

Option C is correct.

Step-by-step explanation:

We need to find area of triangle ABC

We are given A(2,1) B(4,7) and C(6,3)

The formula used to find $Area \ of \ triangle=\frac{1}{2}base\times height$ ABC is:

In the given triangle base= AC and height = BC

First we need to find the distance between A and C and B and C

The formula used to find distance between AC $Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have $x_1=2, y_1=1, x_2=6, y_2=3$

Putting values and finding distance

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(6-2)^2+(3-1)^2}\\Distance=\sqrt{(4)^2+(2)^2}\\Distance=\sqrt{16+4}\\Distance=\sqrt{20}$

find distance between BC $Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have $x_1=4, y_1=7, x_2=6, y_2=3$

Putting values and finding distance

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(6-4)^2+(3-7)^2}\\Distance=\sqrt{(2)^2+(4)^2}\\Distance=\sqrt{4+16}\\Distance=\sqrt{20}$

So, We have height = $\sqrt{20}$ and base = $\sqrt{20}$

Finding area of triangle

$Area \ of \ triangle=\frac{1}{2}base\times height\\Area \ of \ triangle=\frac{1}{2}\sqrt{20} \times \sqrt{20} \\Area \ of \ triangle=\frac{1}{2}\times 20\\Area \ of \ triangle=10$

So, Area of triangle ABC = 10

Option C is correct.

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3 years ago

Describe how to write 6,397,000,000 in scientific notation.

Gnoma [55]

Answer:

6.397 × 10^9

Step-by-step explanation:

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3 years ago

The area of a square is (9a2 − 24a + 16) square units. determine the length of each side of the square by factoring the area exp

Anton [14]

The will be 3x+4 I hope this help you

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3 years ago