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allochka39001 [22]
3 years ago
13

What is the area of ABC?

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
7 0

Answer:

Area of triangle ABC = 10

Option C is correct.

Step-by-step explanation:

We need to find area of triangle ABC

We are given A(2,1) B(4,7) and C(6,3)

The formula used to find Area \ of \ triangle=\frac{1}{2}base\times height ABC is:

In the given triangle base= AC and height = BC

First we need to find the distance between A and C and B and C

The formula used to find distance between AC Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have x_1=2, y_1=1, x_2=6, y_2=3

Putting values and finding distance

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(6-2)^2+(3-1)^2}\\Distance=\sqrt{(4)^2+(2)^2}\\Distance=\sqrt{16+4}\\Distance=\sqrt{20}

find distance between BC Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have x_1=4, y_1=7, x_2=6, y_2=3

Putting values and finding distance

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(6-4)^2+(3-7)^2}\\Distance=\sqrt{(2)^2+(4)^2}\\Distance=\sqrt{4+16}\\Distance=\sqrt{20}

So, We have height = \sqrt{20} and base = \sqrt{20}

Finding area of triangle

Area \ of \ triangle=\frac{1}{2}base\times height\\Area \ of \ triangle=\frac{1}{2}\sqrt{20} \times \sqrt{20} \\Area \ of \ triangle=\frac{1}{2}\times 20\\Area \ of \ triangle=10

So, Area of triangle ABC = 10

Option C is correct.

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Answer:

Step-by-step explanation:

We know the perimeter of a triangle is the sum of all the sides( two legs and one hypotenuse).

By pythagoras we know that

h^2= a^2+b^2.

and the perimeter is P=h+a+b.

Since P=24 and a=6  we have these equations:

h^2=36+b^2\\24=h+6+b

From the last equation we have h=18-b. Replace h in the first equation we get that

(18-b)^2=36+b^2

18^2-36b+b^2=36+b^2\\288=36b\\b=\frac{288}{36}=8

and h=18-8=10

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The answer to this problem would be 0.0492.

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a cafe sells a regular cup of coffee for $1 and a large sup for $1.50. melissa and her friend buy 5 cups of coffee and spend a t
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Find Distance (4,6) (-4,-3)​
vampirchik [111]

Answer:

\sqrt{145}

Step-by-step explanation:

The distance formula states that the distance between two points (a,b) and (c,d) is \sqrt{(a-c)^2+(b-d)^2}.

The two points we have are (4,6) and (-4,-3). Plugging these numbers into the distance formula, we have

\sqrt{(4-(-4))^2+(6-(-3))^2.

Simplifying with order of operations, first using the distributive property, gives

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Squaring and adding gives

\sqrt{(4+4)^2+(6+3)^2}=\sqrt{8^2+9^2}\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~=\sqrt{64+81}\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~=\boxed{\sqrt{145}},

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2 years ago
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