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3 years ago

Please HELP!!

Mathematics

1 answer:

tensa zangetsu [6.8K]3 years ago

5 0

Answer:

66.5%

Step-by-step explanation:

The average of 63% and 70% is

(63%+70%)/2=66.5%

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Answer:

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8 0

3 years ago

First try was incorrect

KiRa [710]

Answer:

12 presents

Step-by-step explanation:

4/6= 2/3

2/3 x 18 = 12

5 0

3 years ago

A pair of shoes costs $29.99 and the state sales tax is 5%. Use the formula C = p + rp to find the total cost of the shoes, wher

Lemur [1.5K]

29.99 + .05 × 29.99 = 31.49

6 0

3 years ago

Given the definitions of f(x) and g(x) below, find the value of g( f(-5)).

tensa zangetsu [6.8K]

Answer:

we conclude that:

g(f(-5)) = 30

Step-by-step explanation:

Given

f(x) = x+9

g(x) = x² + 7x – 14

To determine

g(f(-5)) = ?

First, we need to find f(-5)

f(x) = x+9

substitute x = -5

f(-5) = (-5)+9

f(-5) = -5+9

f(-5) = 4

g(f(-5)) = g(4)

Now, we need to find g(4)

g(x) = x² + 7x – 14

substitute x = 4

g(4) = (4)² + 7(4) - 14

g(4) = 16 + 28 - 14

g(4) = 30

i.e.

g(f(-5)) = g(4) = 30

Therefore, we conclude that:

g(f(-5)) = 30

7 0

3 years ago

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an

sleet_krkn [62]

Answer:

-6re−r [sin(6θ) - cos(6θ)]

Step-by-step explanation:

the Jacobian is ∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ

x = e−r sin(6θ), y = er cos(6θ)

δx/δθ = -6rcos(6θ)e−r sin(6θ), δx/δr = -sin(6θ)e−r sin(6θ)

δy/δθ = -6rsin(6θ)er cos(6θ), δy/δr = cos(6θ)er cos(6θ)

∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ

= -6rcos(6θ)e−r sin(6θ) × cos(6θ)er cos(6θ) - [-sin(6θ)e−r sin(6θ) × -6rsin(6θ)er cos(6θ)]

= -6rcos²(6θ)e−r (sin(6θ) - cos(6θ)) - 6rsin²(6θ)e−r (sin(6θ) - cos(6θ))

= -6re−r (sin(6θ) - cos(6θ)) [cos²(6θ) + sin²(6θ)]

= -6re−r [sin(6θ) - cos(6θ)] since [cos²(6θ) + sin²(6θ)] = 1

6 0

4 years ago