Two boys are throwing a baseball bat back and forth. The ball is 4ft above the ground when it leaves one child's hand with an up ward velocity of 36ft/s. If acceleration due to gravity is -16ft/s^2, how high above the ground is the ball 2 s after it is thrown? A) 12ft
B) 20ft
C) 76ft
D) 116ft
2 answers:
Answer:
12 ft
Step-by-step explanation:
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That's a typo...if the acceleration of gravity is -16ft/s^2??? Maybe basketball on Mars :P Free fall equation result from integration of the acceleration equation with respect to time... a=g v=gt+v0 h=gt^2/2+v0t+h0 where v0 and h0 are initial velocity and height respectively.. Since acceleration, g, is about -32ft/s^2 not -16ft/s^2 you get: h=-16t^2+36t+4 for your height equation. h(2)=12 ft
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