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harina [27]
3 years ago
12

Which could be the vertices of triangle W? A. X(–2, 2), Y(–10, 2), Z(–6, 10) B. X(2, 2), Y(4, 2), Z(3, 4) C. X(0, 2), Y(4, 2), Z

(2, –6) D. X(2, 2), Y(2, 6), Z(4, 6)
Mathematics
1 answer:
kirill [66]3 years ago
5 0

Answer:

A. B. C. D. E. F. G. H. I. J. K. L. M. N. O. P. Q. R. S. T. U. V. W. X. Y. Z

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Someone answer please, its a test. will give brainliest to the fastest.
MariettaO [177]

Answer:

is there no question you have?

6 0
3 years ago
What sample size would be required to estimate the true proportion of American female business executives who prefer the title "
monitta

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{2.326})^2}=2164.1104

And rounded up we have that n=2165

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

p represent the real population proportion of interest

\hat p represent the estimated proportion for the sample

n is the sample size required (variable of interest)

z represent the critical value for the margin of error

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 98% of confidence, our significance level would be given by \alpha=1-0.98=0.02 and \alpha/2 =0.01. And the critical value would be given by:  

z_{\alpha/2}=-2.326, z_{1-\alpha/2}=2.326

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

And on this case we have that ME =\pm 0.025 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

(b)

We can assume that the estimated proportion is 0.5 since we don't have other info provided to assume a different value. And replacing into equation (b) the values from part a we got:  

n=\frac{0.5(1-0.5)}{(\frac{0.05}{2.326})^2}=2164.1104

And rounded up we have that n=2165

7 0
3 years ago
A random sample of 25 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 9 and the sample standa
Maurinko [17]

Answer:

1.) Yes, because the x distribution is mound-shaped and symmetric and σ is unknown. ;

df = 24 ;

H0 : μ = 8.5

H1 : μ ≠ 8.5 ;

1.250 ;

At the α = 0.05 level, we fail to reject the null hypothesis and conclude the data are not statistically significant.

There is insufficient evidence at the 0.05 level to reject the null hypothesis.

Step-by-step explanation:

Given :

Sample size, n = 25

xbar = 9 ; Standard deviation, s = 2

α = 0.05 ;

The degree of freedom, df = n - 1 ; 25 - 1 = 24

The hypothesis (two tailed)

H0 : μ = 8.5

H1 : μ ≠ 8.5

The test statistic :

(xbar - μ) ÷ (s/√(n))

(9 - 8.5) ÷ (2/√(25))

0.5 / 0.4

Test statistic = 1.250

The Pvalue from Tscore ;

Pvalue(1.250, 24) = 0.2234

Pvalue > α ; We fail to reject H0 ;

8 0
3 years ago
5/9 divided 15 in simplest form
mihalych1998 [28]

\bf \cfrac{5}{9}\div 15\implies \cfrac{5}{9}\div \cfrac{15}{1}\implies \cfrac{5}{9}\cdot \cfrac{1}{15}\implies \cfrac{1}{9}\cdot \cfrac{5}{15}\implies \cfrac{1}{9}\cdot \cfrac{1}{3}\implies \cfrac{1}{27}

8 0
3 years ago
HELP PLEASEEE!!!!1!!!!
12345 [234]

Answer: 1. Dilation.

Step-by-step explanation: All of these transformations do not change the shape's form except for a dilation. It is nessacary to change the shape, so it is a dilation.

7 0
2 years ago
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