The answe is c and also u only divided the denominator not the whole fraction I’m waffling
The answer is True.
Explanation:
Let a = major axis
Let b = minor axis
Let c = focal length.
Consider the right focus, located a distance c from the center of the ellipse (at the origin).
From the right focus to the right point on the major axis is equal to a-c. This is the minimum distance.
From the right focus to the left point on the major axis is equal to a+c. This is the maximum distance.
Answer:
A.)
H0: μ ≤ 31
H1: μ > 31
B.)
H0: μ ≥ 16
H1: μ < 16
C.)
Right tailed test
D.)
If Pvalue is less than or equal to α ; we reject the Null
Step-by-step explanation:
The significance level , α = 0.01
The Pvalue = 0.0264
The decision region :
Reject the null if :
Pvalue < α
0.0264 > 0.01
Since Pvalue is greater than α ; then, we fail to reject the Null ;
Then there is no significant evidence that the mean graduate age is more Than 31.
B.)
H0: μ ≥ 16
H1: μ < 16
Null Fluid contains 16
Alternative hypothesis, fluid contains less than 16
One sample t - test
C.)
Null hypothesis :
H0 : μ ≤ 12
. The direction of the sign in the alternative hypothesis signifies the type of test or tht opposite direction of the sign in the null hypothesis.
Hence, this is a right tailed test ; Alternative hypothesis, H1 : μ > 12
d.)
If Pvalue is less than or equal to α ; we reject the Null.
The length of the repel line using one of the 3 trigonometry ratios will be 186.78 feet.
<h3>How to calculate the length?</h3>
From the information given, Peyton is walking her dog, Willow, on a local trail and the dog falls 153 feet down a ravine.
The length will be calculated thus:
Cos 35° = 153/AC.
AC = 153/cos 35°
AC = 153/0.819
AC = 186.78 feet.
Therefore, the length is 186.78 feet.
Learn more about length on:
brainly.com/question/2217700
Answer:
<em>Alex sold 330 white chocolate bars</em>
Step-by-step explanation:
let the milk chocolate candy be x and the white chocolate candy be y. then
then 2x+3y=990----1)
x+y=330-----2)
from eq 2) ⇒ x=330-y---------3)
Putting eq 3 in eq 1
2(330-y) +3y=990
660-2y+3y=990
y=990-660=330-----------4)
Putting eq4 in eq1
2x+3(330)=990
2x+990=990
2x=990-990
2x=0
x=0---------------------------5)
