Good morning
Answer:
NO
Step-by-step explanation:
Here we just substitute x and y by their values and see if the inequality still true or not
y = 3
6x + 3 = 6(2) + 3 = 15
since 3 < 15 then the inequality y > 6x + 3 is wrong.
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:)
I believe the correct answer from the choices listed above is the first option. If the sides of a square are five to the power of two fifths inches long, then the are of the square would be <span>five to the power of four fifths square inches. Hope this answers the question.</span>
since we know those two triangles are similar then we can use proportions.
![\cfrac{AE}{AB}=\cfrac{AD}{AC}\implies \cfrac{14-8}{2x}=\cfrac{14}{2x+4}\implies \cfrac{6}{2x}=\cfrac{14}{2x+4}\implies \cfrac{3}{x}=\cfrac{14}{2x+4} \\\\\\ 6x+12=14x\implies 12=8x\implies \cfrac{12}{8}=x\implies \cfrac{3}{2}=x \\\\[-0.35em] ~\dotfill\\\\ AB=2x+4\implies AB=2\left( \frac{3}{2} \right)+4\implies AB=3+4\implies AB=7](https://tex.z-dn.net/?f=%5Ccfrac%7BAE%7D%7BAB%7D%3D%5Ccfrac%7BAD%7D%7BAC%7D%5Cimplies%20%5Ccfrac%7B14-8%7D%7B2x%7D%3D%5Ccfrac%7B14%7D%7B2x%2B4%7D%5Cimplies%20%5Ccfrac%7B6%7D%7B2x%7D%3D%5Ccfrac%7B14%7D%7B2x%2B4%7D%5Cimplies%20%5Ccfrac%7B3%7D%7Bx%7D%3D%5Ccfrac%7B14%7D%7B2x%2B4%7D%20%5C%5C%5C%5C%5C%5C%206x%2B12%3D14x%5Cimplies%2012%3D8x%5Cimplies%20%5Ccfrac%7B12%7D%7B8%7D%3Dx%5Cimplies%20%5Ccfrac%7B3%7D%7B2%7D%3Dx%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20AB%3D2x%2B4%5Cimplies%20AB%3D2%5Cleft%28%20%5Cfrac%7B3%7D%7B2%7D%20%5Cright%29%2B4%5Cimplies%20AB%3D3%2B4%5Cimplies%20AB%3D7)
Answer:
Option 4
Step-by-step explanation:
See the attached image.
The first on is 21 miles . The second is yes . It’s 2 miles closer I believe
