<h2><u>
Answer:</u></h2>


<em>I hope this helps you</em>
<em>:)</em>
Let S represent the cost of a small box, and L represent the cost of a large box.
Matt's sale can be represented by the equation
3S +14L = 203
Ming's sale can be represented by the equation
11S +11L = 220
There are a number of ways to solve a pair of equations. One is to graph them. The graph shows the costs to be ...
The cost of a small box of oranges is $7. The cost of a large box of oranges is $13.
The answer would be 4 over 5 or 4/5
Answer:
- first mechanic: $105/hour
- second mechanic: $55/hour
Step-by-step explanation:
Let r represent the rate charged by the first mechanic. Then 160-r is the rate charged by the second mechanic. The total of charges is ...
20r +5(160-r) = 2375
15r +800 = 2375 . . . . . . eliminate parentheses
15r = 1575 . . . . . . . . . . . . subtract 800
r = 105 . . . . . . . . . . . . . . . divide by 15. First mechanic's rate.
160-r = 55 . . . . . Second mechanic's rate
The first mechanic charged $105 per hour; the second, $55 per hour.