Answer:
t = 1.068 s
Step-by-step explanation:
given,
a(t) =- k v(t)
speed of the object decreases from 800 ft/s to 700 ft/s
distance = 1400 ft
time for deceleration = ?
a(t) =- k v(t)


integrating both side


..........(1)
since,



![1400= -\dfrac{800}{k}[e^{-kt}-e^0]](https://tex.z-dn.net/?f=1400%3D%20-%5Cdfrac%7B800%7D%7Bk%7D%5Be%5E%7B-kt%7D-e%5E0%5D)
from equation 1
![k= -\dfrac{8}{14}[\dfrac{7}{8}-1]](https://tex.z-dn.net/?f=k%3D%20-%5Cdfrac%7B8%7D%7B14%7D%5B%5Cdfrac%7B7%7D%7B8%7D-1%5D)

putting value of k in equation (1)

t = 1.068 s
Answer:
4*(-10-(-3))=-52
Step-by-step explanation:
just step by step
X = k/p^3
125 = k/10^3 = k/1000
1000 x 125 = k
k = 125000
x = 125000/p^3
The profit is given by G = px - (125 + 2x) = p(125000/p^3) - 125 - 2(125000/p^3) = 125000/p^2 - 250000/p^3 - 125
For maximum profit:
dG/dp = 0
dG/dp = -250000/p^3 + 750000/p^4 = 0
750000 - 250000p = 0
p = 750000/250000 = 3
Therefore the price that will yeaild maximum profit is $3.
Answer:
6d-30
Step-by-step explanation:
6(d-5)
6d-30 distributive property