Answer:
Option-D is the correct answer.
Explanation:
Hydrocarbons are classified as;
a) Saturated Hydrocarbons:
Those hydrocarbons in which all carbon atoms are bonded to each other through a single covalent bonds are known as Saturated Hydrocarbons.
Example:
Alkanes with a general formula CnH₂n+₂ belongs to saturated hydrocarbons. The Hydrogen Deficiency Index of Alkanes is zero, means it does not contain any double or triple bond.
i) H₃C-CH₃ Ethane
ii) H₃C-CH₂-CH₃ Propane
iii) H₃C-CH₂-CH₂-CH₃ Butane
b) Unsaturated Hydrocarbons:
Those hydrocarbons in which a double bond (Alkenes) or triple bond (Alkynes) is formed between two carbon atoms are called as unsaturated Hydrocarbons.
Example:
Alkene with a general formula CnH₂n belongs to unsaturated hydrocarbons. The minimum Hydrogen Deficiency Index of Alkenes is one, means it contain minimum one double bond.
i) H₂C=CH₂ Ethene
ii) H₂C=CH-CH₃ Propene
iii) H₃C-CH=CH-CH₃ 2-Butene
Alkyne with a general formula CnH₂n-₂ belongs to unsaturated hydrocarbons. The minimum Hydrogen Deficiency Index of Alkynes is two, means it contain minimum one triple bond.
i) HC≡CH Ethyne
ii) HC≡C-CH₃ Propyne
iii) H₃C-C≡C-CH₃ 2-Butyne
The volume of HCOOH is 0.003 Lt and the volume of HCOONa is 0.017 LT.
Explanation:
For acidic buffer
PH = Pka + log
4.25 = 3.75 + log
log = 0.75
log = 5.62 is considered as equation 1.
Let V₁ ml of HCOOH and V₂ml of HCOONA was mixed and the final volume is 100 ml .
V₁ *0.5 + V₂ *0.5 =0.1 * 100
V₁+V₂ = = 20 is the second equation.
Now concentration of salt and acid are
V₂ [salt] = 0.5/100 and v₁ [acid] = 0.5/100
by substituting these in equation 1 we get,
= 5.62
V₂ = V₁ * 5.62 is the 3 rd equation
by solving 2 and 3 we get,
5.62 V₁ + V₁ = 20
= 6.62 V₁ = 20
V₁ = 3.02 ml
V₁ = 0.003 LT
V₂ = V₁ * 5.62
V₂ = 0.017 LT
Hence the volume of HCOOH is 0.003 Lt and the volume of HCOONa is 0.017 LT.
Density = mass / volume
8.96 = m / 7.00
m = 8.96 x 7.00
m = 62.72 g
Answer:
francium
Explanation:
the atomic radius increases from top to bottom in a group, and decreases from left to right across a period.