1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sergiy2304 [10]
3 years ago
9

The chemical equation shows iron(III) phosphate reacting with sodium sulfate. 2FePO4 + 3Na2SO4 Fe2(SO4)3 + 2Na3PO4 What is the t

heoretical yield of Fe2(SO4)3 if 20.00 g of FePO4 reacts with an excess of Na2SO4
Chemistry
1 answer:
slava [35]3 years ago
8 0

<u>Answer:</u> The theoretical yield of iron(III) sulfate is 26.6 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of iron(III) phosphate = 20.00 g

Molar mass of iron(III) phosphate = 150.82 g/mol

Putting values in equation 1, we get:

\text{Moles of iron(III) phosphate}=\frac{20g}{150.82g/mol}=0.133mol

The given chemical equation follows:

2FePO_4+3Na_2SO_4\rightarrow Fe_2(SO_4)_3+2Na_3PO_4

As, sodium sulfate is present in excess. So, it is considered as an excess reagent.

Thus, iron(III) phosphate is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of iron(III) phosphate produces 1 mole of iron(III) sulfate

So, 0.133 moles of iron(III) phosphate will produce = \frac{1}{2}\times 0.133=0.0665moles of iron(III) sulfate

Now, calculating the mass of iron(III) sulfate from equation 1, we get:

Molar mass of iron(III) sulfate = 399.9 g/mol

Moles of iron(III) sulfate = 0.0665 moles

Putting values in equation 1, we get:

0.0665mol=\frac{\text{Mass of iron(III) sulfate}}{399.9g/mol}\\\\\text{Mass of iron(III) sulfate}=(0.0665mol\times 399.9g/mol)=26.6g

Hence, the theoretical yield of iron(III) sulfate is 26.6 grams

You might be interested in
List the three requirements for a correctly written chemical equation.2. Give one example of a word equation, one example of a f
erma4kov [3.2K]

Answer:

Requirements for a correctly written chemical equation are reactants and products, their formula and valency

Explanation:

Formula of the given compound are -

1 - Potassium Hydroxide - KOH

2 - Calcium Nitrate - Ca(NO_3)_2

The requirements for a correctly written chemical equation are -

  • Identifying reactants and products
  • Formula of reactants and products
  • Valency of elements

Example of word equation, formula equation, and chemical equation is as follows -

Aluminium + iron9(III)oxide ⇒ aluminium oxide + iron (word equation)

Al_(_s_)  + Fe_2O_3_(_s_)    ⇒   Al_2O_3_(_s_)  + Fe_(s) (formula equation)              

2Al_(_s_) + Fe_2O_3_(_s_)    ⇒   Al_2O_3_(_s_)   + 2Fe_(_s_) (chemical equation)

8 0
3 years ago
the most common source of copper (Cu) is the mineral chalcopyrite (CuFeS2). How many kilograms of chalcopyrite must be mined to
lara [203]
<span>0.650 kg... I think, 
But what are the answer choices?</span>
3 0
4 years ago
Suppose you used 0.5 M NaOH to titrate your vinegar sample instead of 0.1 M. What effect does the concentration of base added ha
laiz [17]

Answer: the reliability will be worse

Explanation:

Suppose we used 0.5 M NaOH to titrate our vinegar sample instead of 0.1 M.

Now by using 0.5M instead of 0.1M we are increasing the concentration of NaOH,

We know that  the moles used = Volume x concnetration.

so for the same no of moles, if the concentration increases, the volume decreases.

Hence it will consume less NaOH.

now Since the volume decreases, the titration volume of less number will increase the % error.

Therefore the reliability will be worse.      

4 0
2 years ago
What happens when the thermal energy of a substance increases?
MariettaO [177]

Answer:

Explanation:

Both motion of particles and temperature increase

8 0
3 years ago
Read 2 more answers
What is the molarity of the solution resulting from the dissolution of 239 g glucose (C6H12O6) in 250
kifflom [539]

Answer:

Molarity =5.32 M

Explanation:

Given data:

Mass of glucose = 239 g

Volume = 250 mL (250 /1000 = 0.25 L)

Molarity = ?

Solution;

Formula:

Molarity = number of moles / volume in litter

Number of moles:

Number of moles = mass/ molar mass

Number of moles = 239 g / 180.2 g/mol

Number of moles = 1.33 mol

Molarity:

Molarity = number of moles / volume in litter

Molarity = 1.33 mol / 0.25 L

Molarity =5.32 M

6 0
3 years ago
Other questions:
  • To support a child's self-esteem, you can make all of these statements, except
    10·1 answer
  • Calculate the amount of heat energy, in kJ, needed to increase the temperature of 200g of water by 300 C.
    15·1 answer
  • What is the difference between magma and lava?
    6·1 answer
  • What is the force needed to accelerate a 25 kg object at 3 m/s²? Formula ( F = m x a)
    9·2 answers
  • 6. Steel is a metallic-like material but it is not a pure element. It is a alloy.
    7·1 answer
  • If 6.75 g of NaOH are dissolved in 50.00 g of water and the temperature increases
    11·1 answer
  • How many molecules are in 10 grams of sugar?
    10·1 answer
  • Maya has an attached earlobe. What is responsible for Maya’s ear shape?
    15·1 answer
  • Why is the first one (A) correct?
    11·1 answer
  • What number of moles of O2(g) is required to react with 3.6 mol SO2(g) in the following
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!