Question

Read the chemical equation. N2 + 3H2 → 2NH3 Using the volume ratio, determine how many liters of NH3 is produced if 1.2 liters of H2 reacts with an excess of N2, if all measurements are taken at the same temperature and pressure? 1.8 liters 1.5 liters 0.90 liters 0.80 liters

Answer 1

its 0.80 liters

im doing the exam rn

Answer 2

Answer : The volume of $NH_3$ produced will be, 0.8 liters.

Explanation : Given,

Volume of $H_2$ = 1.2 L

At STP, 1 mole of substance contains 22.4 L volume of substance.

The given balanced chemical reaction is:

$N_2+3H_2\rightarrow 2NH_3$

From the balanced chemical reaction we conclude that,

As, $3\times 22.4L$ volume of $H_2$ produced $2\times 22.4L$ volume of $NH_3$

So, $1.2L$ volume of $H_2$ produced $\frac{2\times 22.4L}{3\times 22.4L}\times 1.2L=0.8L$ volume of $NH_3$

Therefore, the volume of $NH_3$ produced will be, 0.8 liters.