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Dmitry_Shevchenko [17]
3 years ago
10

Find two numbers, if their sum is −11 and their difference is 41

Mathematics
1 answer:
snow_tiger [21]3 years ago
3 0

The larger one is (-11 + 41)/2 = 15.

The smaller one is (-11 -41)/2 = -26.

_____

For two numbers a and b with sum s and difference d, you can write the equations

a+b=s\\a-b=d

Then adding the equations and dividing that sum by 2, you get

(a+b)+(a-b)=(s)+(d)\\2a=s+d\\a=\dfrac{s+d}{2}

You can subtract the second eqution from the first and get a similar result for the smaller number

(a+b)-(a-b)=(s)-(d)\\2b=s-d\\b=\dfrac{s-d}{2}

These are the formulas we used above.

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