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VMariaS [17]
3 years ago
11

Find the exact value of cos 45º in simplest form with a rational denominator.​

Mathematics
1 answer:
goldenfox [79]3 years ago
8 0

Answer:

\frac{\sqrt{2} }{2}

Step-by-step explanation:

Cos is Adjacent over Hypotenuse, (see picture below)

x/xsqrt(2)

1/sqrt(2)

sqrt(2)/2

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After a birthday only 1/4 cake ramains what fraction is equivalent 1/4
victus00 [196]

Answer:

2/8, 3/12, 4/24, 5/20, 6/24, 7/28, 8/32, 9/36, 10/40, etc.

Step-by-step explanation:

3 0
3 years ago
Subtracting fractions...please show your work and out in simplest form
Neporo4naja [7]
For (A.) Get a common denominator, 40/12 - 9/12 = 31/12 or (2 and 7/12)
For (B.) Get a common denominator, 24/15 - 10/15 = 14/15 (Simplified)
For (C.) Get a common denominator, 51/30 - 25/30 = 26/30 or (13/15)
For (D.) Get a common denominator, 14/6 - 9/6 = 5/6 (Simplified)

Hope this helps!
PS: (Rate me brainliest?)
3 0
3 years ago
Correct answer gets brainliest!!<br><br> Does someone know the answers to these question
VARVARA [1.3K]

Use Ga_thMath(u) (brainly doesn't allow me to type it) To use the app u need to take a pic of the problem and then it will process it and you'll get ur answer ASAP(most of the time). Many questions have been asked before so search it on brainly.

4 0
3 years ago
ACTIVITY 2 (19) Mr Duma recently inherited a rectangular plot, part of the estate left by his late father. The plot with the fol
seraphim [82]

The sum of the lengths of three sides of the rectangle, gives the length

of the fencing, while one third of the rectangle area is for the pavement.

Responses:

Project A: The formula for the length of the fencing is, L = 4·x - 1

Project B: Length of the fancy wall = 2·x + 1

Project \ C:Area \ of \ the \ paving = \underline{ \dfrac{2\cdot x^2 }{3} - \dfrac{x }{3}  - \dfrac{1}{3}}

<h3>Which method can be used to find the length and area of paving from the given equations?</h3>

Project A: Let QP and SR represent the longest sides of the rectangle, we have;

PQ = SR = 2·x + 1

Given parameters are;

Length of the rectangular plot = 2·x + 1

Width of the rectangular plot = x - 1

Vertices of the rectangular plot are; QPSR

Project A: Let QP and SR represent the longest sides of the rectangle, we have;

PQ = SR = 2·x + 1

Which gives;

SP = QR = x - 1

The length of the fencing, L = SP + PQ + QR = x - 1 + 2·x + 1 + x - 1 = 4·x - 1

  • The formula for the length of the fencing is, L =<u> 4·x - 1</u>

Project B: The front side is SR

Therefore;

  • Length of the fancy wall = <u>2·x + 1</u>

Project C:

Area, A = Length × Width

Area of the plot, A = (2·x + 1) × (x - 1) = 2·x² - x - 1

  • Area \ of \ the \ paving = \dfrac{1}{3} \times \left(2 \cdot x^2 - x - 1\right) = \underline{ \dfrac{2\cdot x^2 }{3} - \dfrac{x }{3}  - \dfrac{1}{3}}

Learn more about writing equations here:

brainly.com/question/24760633

6 0
2 years ago
Please answer this math
ohaa [14]
6 cm squared I believe
3 0
3 years ago
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