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mars1129 [50]
2 years ago
14

McKenzie spilled 22 pints of water in 4 days. Avery collected 14 pints of water in 3 days . How many pints did each of them lose

or gain per day?
Mathematics
1 answer:
USPshnik [31]2 years ago
7 0

Step-by-step explanation:

MaKenzie spilled 5 1/2 pints per day

Avery collected 4 2/3 pints per day

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A pro baseball team is having a promotion in which every 10th fan that enters the stadium gets a free hat and every 12th person
mixas84 [53]
Multiples of 10 = 10, 20, 30, 40, 50, 60
This means the 10th, 20th, 30th, 40th, 50th, 60th, ... fan will get a free hat.
Multiples of 12 = 12, 24, 36, 48, 60
This means the 12th, 24th, 36th, 48th, 60th, ... fan will get a free shirt.
So the 60th fan will receive both a hat and a shirt.
Meaning 60 fans will come to the stadium before a fan receives both a hat and a shirt.
3 0
3 years ago
Pls help!!! if f(x) = 3x-2 and g(x) = 6-4x, fibd f(x) + g(x)
sp2606 [1]
So first off the equation we are solving is f(x) + g(x). So i want to plug in those equations first off. The new equation I get should be 3x-2 + 6 -4x. I then simplify this to -x+4 or 4-x.
6 0
3 years ago
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20000 students took a standardized math test. The scores on the test are normally distributed, with a mean score of 85 and a sta
Tpy6a [65]

Answer: 2718

Step-by-step explanation:

Given: Mean score = 85

Standard deviation = 5

Let x be the score of a random student that follows normal distribution.

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P(90< x < 95)\\\\=P(\dfrac{90-85}{5}

The number of students scored between 90 and 95 = 0.1359 x (Total students)

= 0.1359 (20000)

= 2718

Hence, The number of students scored between 90 and 95 = 2718

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=7%20-%209w%20%3D%20%20-%2029%20" id="TexFormula1" title="7 - 9w = - 29 " alt="7 - 9w = - 29
Oksana_A [137]
7 - 9w = - 29

Subtract 7 from both sides

- 9w = - 36

Divide by - 9 on both sides

w = 4
5 0
3 years ago
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Plz solve this if u know plz​
salantis [7]
<h3>Solution:</h3>

{64}^{ -  \frac{1}{3} } ( {64}^{ \frac{1}{3} }  -  {64}^{ \frac{2}{3} } ) \\  {64}^{ \frac{1}{3} -  \frac{1}{3}  }  -  {64}^{ \frac{2}{3}  -  \frac{1}{3} }  \\  {64}^{0}  -  {64}^{ \frac{1}{3} }  \\ 1 -  \sqrt[3]{64}  \\ 1 - 4 \\  - 3

<h3>Answer:</h3>

- 3

5 0
3 years ago
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