Answer:
The answer is below
Explanation:
Given that we need to have two or more arithmetic means inserted between two arithmetic extremes, then we have
d= (an - ak) ÷ ( n - k)
For Example: What are the three arithmetic means of the arithmetic extremes 8 and 16, then a1= 12, and a5= 20?
First we use the formula:
d= (an - ak) ÷ (n - k)
= (20 - 12 ) ÷ (5 - 1)
=> (8) ÷ (4) = 2
Our common difference is 2.
Then we can simply:
a5 = 20
a4 = 20 - 2(1) = 18
a3 = 20 - 2(2) = 16
a2 = 20 - 2(3) = 14
a1 = 20 - 2(4) = 12
Now we have our arithmetic sequence 12, 14, 16, 18, 20
Therefore the three arithmetic means of the arithmetic extremes 12 and 20 ==> 14, 16 and 18.
