The answer is D
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Answer:
The cost of one rose is $11., and the cost of one geranium is $5.
Step-by-step explanation:
The cost of one rose bush and one geranium can be determined by the use of simultaneous equation. Let the cost of a rose bush be represented by x, and the cost of one geranium by y.
So that,
13x + y = 148 .............. 1
9x + 14 y = 169 ............... 2
From eqaution 1,
y = 148 - 13x ............... 3
substitute the value of y in equation 2
9x + 14(148 - 13x) = 169
9x + 2072 - 182x = 169
2072 - 169 = 182x - 9x
1903 = 173x
x = 
= 11
x = 11
substitute the value of x in equation 3
y = 148 - 13x
= 148 - 13(11)
= 148 - 143
y = 5
x = 11, y = 5
Thus, the cost of one rose is $11., and the cost of one geranium is $5.
Answer:
The answer is A parallel
Step-by-step explanation:
I put this in a graphing calculator
Answer:
g(x) = x+1
Step-by-step explanation:
Informally, you can see that the function h(x) takes the root of a value that is 1 more than the value under the same radical in f(x). This suggests that adding 1 to x in f(x) will give you h(x). That is, ...
h(x) = f(x+1) = f(g(x))
so
g(x) = x+1
_____
More formally, you can apply the inverse of the function f(x) to the equation ...
h(x) = f(g(x))
f^-1(h(x)) = f^-1(f(g(x))) . . . inverse function applied
f^-1(h(x)) = g(x) . . . . . . . . . simplified
Now f^-1(x) can be found by solving for y in ...
x = f(y)
x = ∛(y+2) . . . . . . . . . definition of f(y)
x^3 = y+2 . . . . . . . . . cube both sides
x^3 -2 = y = f^-1(x) . . . subtract 2 from both sides
So, f^-1(h(x)) is ...
f^-1(h(x)) = g(x) = (∛(x+3))^3 -2 = x+3 -2
g(x) = x+1
Answer:
Following are the Arithmetic Operators available in Rexx. Operator, Description, Example. +, Addition of two operands, 1 + 2 will give 3
Step-by-step explanation: