The height of the kite above the ground is 58.68 ft
Let x be the height of the kite above Chee's hand.
The height of the kite above Chee's hand, the string and the horizontal distance between Chee and the kite form a right angled triangle with hypotenuse side, the length of the string and opposite side the height of the kite above Chee's hand.
Since we have the angle of elevation from her hand to the kite is 29°, and the length of the string is 100 ft.
From trigonometric ratios, we have
tan29° = x/100
So, x = 100tan29°
x = 100 × 0.5543
x = 55.43 ft.
Since Chee's hand is y = 3.25 ft above the ground, the height of the kite above the ground, L = x + y
= 55.43 ft + 3.25 ft
= 58.68 ft to the nearest hundredth of a foot
So, the height of the kite above the ground is 58.68 ft
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Answer:
<em>(8.21, -20.79)</em>
Step-by-step explanation:
Given the simultaneous equation;
From 2;
a = 29 + b ....3
Substitute 3 into 1;
Factorize
b = -18±√18²-4(-58)/2
b = -18±√324+232/2
b = -18±√556/2
b = -18±23.58/2
b = -18-23.58/2 and -18+23.58/2
b = -41.58/2 and 5.58/2
b = -20.79 and 2.79
Since a = 29 + b
when b = -20.79
a = 29 - 20.79
a = 8.21
<em>Hence the solution to the system of equation is (8.21, -20.79)</em>
Answer:
because l1//l2 => z + 65 = 180
y + 65 = 90
x + 65 = 90
<=> z = 115
y = 25
x = 25
Answer:
y = -3x - 11
Step-by-step explanation:
Use the given slope and point in the point-slope equation. Solving this will give us the y-intercept equation.
Point-slope formula: y - y = m(x - x)
Plug in the slope and point
y - (-5) = -3(x - (-2))
Subtracting negatives will make them positive. Multiply out the -3 to what is in the parentheses.
y + 5 = -3x - 6
Subtract the 5 from both sides
y = -3x - 11
The equation of the line is y = -3x - 11
